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monitta
3 years ago
5

Compare the modeld for one third and two sixths

Mathematics
1 answer:
DochEvi [55]3 years ago
4 0
1/3 is equal to 2/6
This is because 1/3 converted to 6ths you have to multiply 1/3 times 2 which equals 2/6
1/3 = 2/6
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22a) PLEASE HELP BEST ANSWER BRAINLIEST
adoni [48]

Answer:

the answer is k=1

Step-by-step explanation:

8 0
3 years ago
Write down two prime numbers that have a sum of 32​
DaniilM [7]

19 and 13 can be the numbers

hope it helps

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2 years ago
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Find the slope intercept <br>(9,5),(7,-11)<br>y=​
grin007 [14]

Answer:

y=8x-67

Step-by-step explanation:

So the question is what is the equation for the following two coordinate points?

Well to start off what is the formula? The formula is called the linear equation. Which is y=mx+b. What does these letters or "variables" mean or represent?! Welp, m stands for the slope, which is "Δy over Δx." Some people call say "the change of y over x." I call it the rise over run. So it is saying y over x. The b in the linear equation is the y-intercept. The y-intercept is when the line crosses the y-axis.

With that being said, let's find the slope. But how? Well with the Δy over Δx. The formula is y₂-y₁ over x₂-x₁. With the two coordinate points we can label them.

y₂=5

y₁=(-11)

x₂=9

x₁= 7

Now let set it up into the equation of y over x

Slope =  <u> 5- (-11) </u> = <u> 5 + 11  </u> = <u>  16 </u> = 8

                  9-7         9-7          2

So we now have the slope! Which is 8! So put that into the linear equation!

y=8x+b

Next, we need to find b, the y-intercept! How do we do that well, we can figure it out by one of the coordinate points! Let use the (7, -11) point for example! Remember, x= 7 and y= (-11)

(-11) = 8(7) + b

(-11) = 56 + b

<u>-56   -56</u>

-67 =  b

We now have b, which is negative 67! So we need to put all the information we have found into the linear equation!

y=8x-67

6 0
3 years ago
If f(1) = 0, what are all the roots of the function f(x)=x^3+3x^2-x-3? Use the Remainder Theorem.
Sophie [7]
There's no if about it, 

f(x)=x^3+3x^2-x-3&#10;

has a zero f(1)=0 so x-1 is a factor.   That's the special case of the Remainder Theorem; since f(1)=0 we'll get a remainder of zero when we divide f(x) by x-1.

At this point we can just divide or we can try more little numbers in the function.  It doesn't take too long to discover f(-1)=0 too, so  x+1 is a factor too by the remainder theorem.  I can find the third zero as well; but let's say that's out of range for most folks.

So far we have 

x^3+3x^2-x-3 = (x-1)(x+1)(x-r)

where r is the zero we haven't guessed yet.  Again we could divide f(x) by (x-1)(x+1)=x^2-1 but just looking at the constant term we must have

-3 = -1 (1)(-r) = r

so

x^3+3x^2-x-3 = (x-1)(x+1)(x+3)

We check f(-3)=(-3)^3+3(-3)^2 -(-3)-3 = 0 \quad\checkmark

We usually talk about the zeros of a function and the roots of an equation; here we have a function f(x) whose zeros are

x=1, x=-1, x=-3

8 0
2 years ago
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Can Someone help me in this?
My name is Ann [436]

Answer:

You should ask your teacher for help and pay attention in class

Step-by-step explanation:

7 0
2 years ago
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