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monitta
3 years ago
5

Compare the modeld for one third and two sixths

Mathematics
1 answer:
DochEvi [55]3 years ago
4 0
1/3 is equal to 2/6
This is because 1/3 converted to 6ths you have to multiply 1/3 times 2 which equals 2/6
1/3 = 2/6
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Solve the exponential function
nikklg [1K]

Answer:

See below.

Step-by-step explanation:

Just like 18, continue with 19-21. Solve for x by rewriting each equation in log form.

e^x = 4.9\\\\x = ln 4.9\\\\x = 1.59

When rewriting the form, the base of the exponent becomes the base of the log.

8 0
4 years ago
CAN SOME ONE PLEASE ANSWER THIS RIGHT THANK YOU
Galina-37 [17]

Answer:

2:A number is greater than 17.2

Step-by-step explanation:

the ">" in the inequality represents is greater

so the m> means m is greater than... and then the 17.2 means m is greater than 17.2. The way I learnt it was to imagine the ">" sign is like a crocodile, it wants the bigger number. So the ">" being towards the "m" shows that m is the bigger number.

3 0
2 years ago
Read 2 more answers
Factors and common factors of 24,64,88
babunello [35]
24- 1,2,3,4,6,8,12,24
64-1,2,4,8,16,32,64
88-1,2,4,8,11,22,44,88

Here are all the factors.^^
The common factors are 1,2,3,4,6
Hope this helps!
8 0
3 years ago
dylan started working on homework at 5:45 p.m. it took him 1 hour and 57 minutes to complete it what time did
kkurt [141]

I'm assuming its asking what time he finished? I added it up and it seems to be 7:42 pm.

5 0
3 years ago
It's a question from real and complex numbers which I can't solve. so someone PLZ HeLp​
Semmy [17]

Answer:

\frac{1}{5}

Step-by-step explanation:

Using the rules of exponents

a^{m} × a^{n} = a^{(m+n)}, \frac{a^{m} }{a^{n} } = a^{(m-n)}, (a^m)^{n} = a^{mn}

Simplifying the product of the first 2 terms

\frac{a^{p^2+pq} }{a^{pq+q^2} } × \frac{a^{q^2+qr} }{a^{qr+r^2} }

= a^{p^2-q^2} × a^{q^2-r^2}

= a^{p^2-r^2}

Simplifying the third term

5((a^p+r)^{p-r}

= 5a^{(p+r)(p-r)} = 5a^{(p^2-r^2)}

Performing the division, that is

\frac{a^{(p^2-r^2)} }{5a^{(p^2-r^2)} } ← cancel a^{(p^2-r^2)} on numerator/ denominator leaves

= \frac{1}{5}

4 0
3 years ago
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