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3 years ago

12

Kale is hiking 2,345 ft above sea level. The peak of the mountain he is climbing is 3,283 feet above sea level . What is the ver

tical distance between kale and the mountain peak ?
938 ft
942 ft
1,142 ft
5,628

2 answers:

gulaghasi [49]3 years ago

5 0

Answer:

so A. is the correct answer

Step-by-step explanation:

If Kale is at 2345 feet and needs to reach 3283, he will need to travel another 938 feet.

Dmitry_Shevchenko [17]3 years ago

3 0

Answer:

a

Step-by-step explanation:

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10. Jan purchased 140 shares of stock in the ABC Company at a price of $18.75 per share. During the

andre [41]

$\bold{\huge{\orange{\underline{ Solution }}}}$

$\bold{\underline{ Given :- }}$

<u>Jan </u><u>purchased </u><u>1</u><u>4</u><u>0</u><u> </u><u>shares </u><u>of </u><u>stock </u><u>in </u><u>ABC </u><u>company </u><u>at </u><u>a </u><u>price </u><u>of </u><u>$</u><u>1</u><u>8</u><u>.</u><u>7</u><u>5</u><u> </u><u>per </u><u>share </u>
<u>During </u><u>the </u><u>next </u><u>3</u><u> </u><u>days</u><u>, </u><u> </u><u>the </u><u>value </u><u>of </u><u>share </u><u>declined </u><u>by </u><u>$</u><u>1</u><u>.</u><u>0</u><u>0</u><u> </u><u>,</u><u> </u><u>$</u><u>1</u><u>.</u><u>7</u><u>5</u><u> </u><u>and </u><u>$</u><u>1</u><u>.</u><u>5</u><u>0</u>

$\bold{\underline{ To \: Find :- }}$

<u>We </u><u>have </u><u>to </u><u>find </u><u>the </u><u>value </u><u>of </u><u>a </u><u>share </u><u>of </u><u>ABC </u><u>stock </u><u>at </u><u>the </u><u>end </u><u>of </u><u>3</u><u> </u><u>days </u>

$\bold{\underline{ Let's \: Begin :- }}$

<u>According </u><u>to </u><u>the </u><u>question</u><u>, </u>

Cost of 1 share of ABC company = $18.75

<u>Therefore</u><u>, </u>

Cost of 140 shares purchased by Jan in the ABC company

$\sf{ = 140 × 18.75 }$

$\sf{ = 2625\: dollars }$

<u>Now</u><u>, </u>

For next 3 days, the value of share declined

$\sf{ = (1 + 1.75 + 1.50)dollars }$

$\sf{ = 4.25 \: dollars }$

<u>Therefore</u><u>, </u>

The value of shares after 3 days will be

$\bold{ = }{\bold{\frac{2625 - 4.25}{ 140}}}$

$\bold{ = }{\bold{\frac{ 2620.75}{ 140}}}$

$\bold{\red{ = 18.75\: dollars}}$

Hence, The value of share after 3 days will be $18.75 .

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2 years ago

Write the sum of 18+27 as the product of their gcf and another sum

Georgia [21]

Factors of 18: 1; 2; 3; 6; 9; 18

Factors of 27: 1; 3; 9; 27

GCF(18; 27) = 9

<span>18 + 27 = 9 × 2 + 9 × 3 = 9 × (2 + 3) </span>

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3 years ago

Read 2 more answers

Candice leaves on a long trip driving at a steady rate of 35 miles per hour. Her sister Liz leaves from the same location travel

VARVARA [1.3K]

Answer:

<h2>D. 7h</h2>

Step-by-step explanation:

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$\dfrac{-15t_C}{-15}=\dfrac{-150}{-15}\\\\t_C=10\\\\t_L=10-3=7$

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3 years ago

Given cos (theta)=1, find cot (theta)

jok3333 [9.3K]

First problem:

cos (theta)=1

Using the inverse cosine function, you get theta = 0.

Now we find tan 0 = 0

cot(theta) = 1/tan(theta) = 1/0

Division by zero is undefined, so the answer is d. undefined

Second problem:

cos (theta)=1

Use the inverse cosine function.

theta = 0°

Answer: c. 0°

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3 years ago

Suppose the horses in a large stable have a mean weight of 975lbs, and a standard deviation of 52lbs. What is the probability th

Lubov Fominskaja [6]

Answer:

0.8926 = 89.26% probability that the mean weight of the sample of horses would differ from the population mean by less than 15lbs if 31 horses are sampled at random from the stable

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean $\mu$ and standard deviation $\sigma$ , the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean $\mu$ and standard deviation $s = \frac{\sigma}{\sqrt{n}}$ .

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

In this problem, we have that:

$\mu = 975, \sigma = 52, n = 31, s = \frac{52}{\sqrt{31}} = 9.34$

What is the probability that the mean weight of the sample of horses would differ from the population mean by less than 15lbs if 31 horses are sampled at random from the stable?

pvalue of Z when X = 975 + 15 = 990 subtracted by the pvalue of Z when X = 975 - 15 = 960. So

X = 990

$Z = \frac{X - \mu}{\sigma}$

By the Central Limit Theorem

$Z = \frac{X - \mu}{s}$

$Z = \frac{990 - 975}{9.34}$

$Z = 1.61$

$Z = 1.61$ has a pvalue of 0.9463

X = 960

$Z = \frac{X - \mu}{s}$

$Z = \frac{960 - 975}{9.34}$

$Z = -1.61$

$Z = -1.61$ has a pvalue of 0.0537

0.9463 - 0.0537 = 0.8926

0.8926 = 89.26% probability that the mean weight of the sample of horses would differ from the population mean by less than 15lbs if 31 horses are sampled at random from the stable

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3 years ago