Let the lengths of pregnancies be X
X follows normal distribution with mean 268 and standard deviation 15 days
z=(X-269)/15
a. P(X>308)
z=(308-269)/15=2.6
thus:
P(X>308)=P(z>2.6)
=1-0.995
=0.005
b] Given that if the length of pregnancy is in lowest is 44%, then the baby is premature. We need to find the length that separates the premature babies from those who are not premature.
P(X<x)=0.44
P(Z<z)=0.44
z=-0.15
thus the value of x will be found as follows:
-0.05=(x-269)/15
-0.05(15)=x-269
-0.75=x-269
x=-0.75+269
x=268.78
The length that separates premature babies from those who are not premature is 268.78 days
Answer:
16.9 cm
Step-by-step explanation:
The volume of a prism = Area of base × height
For a rectangular prism, the base of the area = length × breadth
The volume of the liquid = 92 L
Since 1 L = 1000 cm³, 92 L = 92000 cm³
92000 = 85 × 64 × h
5440 h = 92000
h = 92000 ÷ 5440 = 16.9 cm
<span>740,679,835 km i hope this helps you
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