Answer:
Same
Step-by-step explanation:
Same tayo ng question
Hello from MrBillDoesMath!
Answer:
2(x+8) = 40
Discussion:
Rewrite the original Question as
"
Twice the (sum of a number and 8) is 40" =>
2 ( x + 8 ) = 40 =>
2 (x+8) = 40
which is the third bullet point from the top
Thank you,
MrB
F(x) =x² - 10x, f⁻¹(x) =?
1st find the missing square of x²-10x, ==> (x-5)² - 25
y= (x-5)² - 25; replace x by y and v0ce versa: x= (y-5)² -25
or
(y-5)² = x+25
y-5 = √(x+25) and y = √(x+25) -5
Domain = {x∈R: X>= 25} AND Range ={y∈R: y>= 5}
Since all the sides add up to 10x+2, that means that 10x-2-<side1>-<side2>=<side3>. Plugging it in, we have 10x-2-5x-(2x+9)=side3, and 5x-2-(2x+9)=side3, then expanding it to 5x-2-2x-9=3x-11=side3
No
X would have to equal 6 or greater as if x was 5
5+3 is the same as 8
