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-Dominant- [34]
3 years ago
7

Dy/dx= y^4 and y(2)= -1. Y(-1)=

Mathematics
1 answer:
cupoosta [38]3 years ago
6 0

It looks like you're asked to find the value of y(-1) given its implicit derivative,

\dfrac{dy}{dx} = y^4

and with initial condition y(2) = -1.


The differential equation is separable:

\dfrac{dy}{y^4} = dx

Integrate both sides:

\displaystyle \int \frac{dy}{y^4} = \int dx

-\dfrac1{3y^3} = x + C

Solve for y :

\dfrac1{3y^3} = -x + C

3y^3 = \dfrac1{-x+C} = -\dfrac1{x + C}

y^3 = -\dfrac1{3x+C}

y = -\dfrac1{\sqrt[3]{3x+C}}

Use the initial condition to solve for C :

y(2) = -1 \implies -1 = -\dfrac1{\sqrt[3]{3\times2+C}} \implies C = -5

Then the particular solution to the differential equation is

y(x) = -\dfrac1{\sqrt[3]{3x-5}}

and so

y(-1) = -\dfrac1{\sqrt[3]{3\times(-1)-5}} = \boxed{\dfrac12}

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