Answer: The omnivorous flock will eat the most as it eats both insects and seeds. With the removal of fruit it will not be affected much. The herbivorous flock will eat the least as it has the option to eat seeds only after the removal of fruit. The flocks all started with 10 birds. Flock was X the most successful at feeding, so it will have the greatest number in the second generation. brainliest?
Explanation:
Answer:
so what's the question asking? does she want to know how much? or the necessary items?
Answer:
logging, and oil exploration
Explanation:
Answer:
Probability of having a child with genotype Ww is 50%.
Explanation:
This question involves a single gene coding for hairline shape in humans. The allele for widow's peak hairline (W) is dominant over the allele for straight hairline (w). This means that allele W will mask the phenotypic expression of allele w in a heterozygous state.
In a cross between a mother with genotype, Ww and father with genotype, ww, the following gametes will be produced by each parent:
Mother (Ww)- W and w
Father (ww)- w and w
Using these gametes in a punnet square (see attached image), four possible offsprings will be produced with genotypes: Ww, Ww, ww and ww.
Ww(2) : ww(2) or Ww(1) : ww(1)
Hence, 1 out of 2 children produced by the parents will have a genotype Ww, i.e. 1/2. Therefore, the percentage probability is 1/2 × 100= 50%.