solve for y
2x−4y=10
-2x -2x subtract -2x from both sides
-4y = -2x +10
-4 -4 Divide both sides by -4 (coefficient on y)
y = -2/-4x + 10/-4
y = 1/2x - 5/2
the slope is the number on the x (coefficient)
and its 1/2
Answer:
y = -2/3x + 6
Step-by-step explanation:
To find the slope, find how much y changes in proportion to x. Here, when x changes by 1, y changes by -2/3. So, the number before x is -2/3.
To find the y-intercept, we need to find what y will be when x is 0. Since we know that when x is 1, y is 16/3, and when x decreases by 1, y increases by 2/3. So, when x is 0, y is 16/3 + 2/3, which is 18/3, or 6.
The answer is for the value of y-coordinate is -5
If we write y=f(x)=(x-h)²+k, then y-k=(x-h)². This is vertex form where the vertex is (h,k)=(3,3) so h and k are both 3. We can see this if we put x=3 in the shifted function. This is a minimum point for the function because for every other x f(x) is greater then 3. The minimum point is the vertex.
Question 6
Given:
QR = RS
QR = x + 6
RS = 4x
To find:
Length of line segment QS
Steps:
We know QR = RS, so substituting we get,
x + 6 = 4x
6 = 4x - x
6 = 3x
6/3 = x
2 = x
x = 2
Now,
QS = QR + RS
QS = x + 6 + 4x
QS = 2 + 6 + 4(2)
QS = 2 + 6 + 8
QS = 8 + 8
QS = 16 units
Therefore, the length of QS is 16 units
Question 7
Given:
QR = RS
QR = 2x - 2
RS = 2x
To find:
Length of line segment QS
Steps:
We know that QR = RS, so substituting the values we get,
QR = RS
3x - 2 = 2x
3x - 2 - 2x = 0
3x - 2x = 2
x =2
Now,
QS = QR + RS
QS = 3x - 2 + 2x
QS = 3(2) - 2 + 2(2)
QS = 6 - 2 + 2(2)
QS = 6 - 2 + 4
QS = 4 + 4
QS = 8 units
Therefore, the length of QS is 8 units
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