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Bingel [31]
4 years ago
8

Which pair of triangles can be proven congruent by SAS?

Mathematics
2 answers:
Verdich [7]4 years ago
6 0

Answer: The first pair of triangles can be proven congruent by SAS.

Step-by-step explanation:

SAS postulate says that if two sides and the included angle of a triangle are equal to two sides and the included angle of another triangle, then the two triangles are said to be congruent.

In the first pair of triangles the included angle of a triangle are equal to two sides and the included angle of another triangle, therefore by SAS postulate the two triangles are said to be congruent.

In the second figure, the pair of triangles are congruent by ASA postulate not SAS.

In the third figure, the pair of triangles are not congruent by any postulate or theorem [Because there is no SSA rule].

In the fourth figure, the pair of triangles are congruent by SSS postulate not SAS.

kow [346]4 years ago
5 0
Hi!
SAS stands for Side Angle Side
So you need two sides and then the angle needs to be between them. 
The first one works because the angle is in-between the 2 sides
The second one doesn't work because there are actually 2 angles and you only need one
The third one doesn't work because the angle isn't between both the sides.
The fourth one doesn't work because there are only sides and no angles. 
So it's only the first one!
Hope this helps!
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ludmilkaskok [199]

The equation of the parallel line in slope-intercept form is;

y = \frac{5}{2} x - \frac{25}{2}

Step-by-step explanation:

Let us revise some facts about parallel lines

The equations of two parallel lines have:

  • Same slopes
  • Different y-intercept

The slope-intercept form of the equation of a line is y = m x + b, where m is the slope of the line and b is the y-intercept

The given line has equation 5x - 2y = 10

Put it in the form of y = m x + b to find its slope

∵ 5x - 2y = 10

- Subtract 5x from both sides

∴ -2y = 10 - 5x

- Divide to sides by -2

∴ y = -5 + \frac{5}{2} x

∴ y =  \frac{5}{2} x - 5

- The value of m is the coefficient of x

∴ m = \frac{5}{2}

∴ The slope of the given line is \frac{5}{2}

∵ Parallel lines have same slopes

∴ The slope of the parallel line is m = \frac{5}{2}

- Substitute the value of m in the form of the equation

∴ The equation of the parallel line is y = \frac{5}{2} x + b

To find b substitute x and y in the equation by the coordinates of any point lies on the line

∵ The parallel line passes through point (3 , -5)

- Substitute x and y by the coordinates of the point (3 , -5)

∵ x = 3 and y = -5

∴ -5 = \frac{5}{2} (3) + b

∴ -5 = \frac{15}{2} + b

- Subtract \frac{15}{2} from both sides

∴ b = \frac{-25}{2}

∴ The equation of the parallel line is y = \frac{5}{2} x + \frac{-25}{2}

∴ The equation of the parallel line is y = \frac{5}{2} x - \frac{25}{2}

The equation of the parallel line in slope-intercept form is;

y = \frac{5}{2} x - \frac{25}{2}

Learn more:

You can learn more about the equations of parallel lines in brainly.com/question/8628615

#LearnwithBrainly

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