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3 years ago

9

The midpoint of AB is M(-2,5). If the coordinates of A are (1,7), what are the coordinates of B?

1 answer:

ratelena [41]3 years ago

5 0

Answer:

(-5, 3)

Step-by-step explanation:

B = 2M - A

B = 2(-2, 5) -(1, 7) = (-4-1, 10-7) = (-5, 3)

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Question 1,2, and 3 how do i factor those? Can you show the work and explain how?

DiKsa [7]

1: $3n^{2}+9n+6$

notice that each part is divisible by 3

$3n^{2}$ ÷ 3 = $n^{2}$

9n ÷ 3 = 3n

6 ÷ 3 = 2

so it becomes $3(n^{2} +3n+2)$

3n can be rewritten as 2n+n

-you want to rewrite it into two numbers that multiply to the number that's alone (in this case 2)

which would get you

$3(n^{2} +2n+n+2)$

Now that it's rewritten, you can factor out n + 2 from the equation.

<u><em>the answer is </em></u>

3(n+2)(n+1)

And you can check that by multiplying (n+2)(n+1) which is $n^{2} +2n+n+2$ and then each of those by 3, which is $3n^{2} +6n+3n+6$ or $3n^{2}+9n+6$ , our origional equation

2: $28+x^{2} -11x$

So I rewrote this as $x^{2} -11x+28$ (it's the same thing, just reordered using the commutative property)

now -11x can be rewritten as -4x-7x

(remember, the two numbers should multiply to equal 28, which is our constant.)

$x^{2} -4x-7x+28$

now we can factor out x from the first expression and -7 from the second

$x(x-4)-7(x-4)$

and lastly you factor out x-4,

<u><em>which would give you</em></u>

(x-4)(x-7)

Make sure to check your work and make sure it multiplies to $x^{2} -11x+28$

3: $9x^{2} -12x+4$

The first thing I notice when looking at this problem is that both 9 and 4 are perfect squares. Not only that, but they are the squares of 2 and 3, which are products of -12

So if you rewrite 9 as $3^{2}$ and 4 as $2^{2}$ , the equation becomes

$3^{2} x^{2} -12x+2^{2}$

now that $3^{2} x^{2}$ is ugly so it can be turned into $(3x)^{2}$

and -12x can be rewritten as $-2*3x*2$

so our equation now looks like $(3x)^2-2*3x*2+2^{2}$

There's a rule that says $a^{2} -2ab+b^{2} = (a-b)^{2}$

In our case, a=3x and b=2

<u><em>so the final answer is</em></u>

$(3x-2)^2$

5 0

2 years ago

I spent 3/4 of my money and then I spent 1/5 of what was left.

Alborosie

1/20 is the fraction that you'll have left

6 0

3 years ago

Use factoring to solve the quadratic equation x2 − 2x − 3 = 12.

melomori [17]

Answer:

$x_1=5\\x_2=-3$

Step-by-step explanation:

You have the following quadratic equation given in the problem:

$x^{2}-2x-3=12$

You must make the equation equal to zero, as following:

$x^{2}-2x-3-12=0$

Add like terms:

$x^{2}-2x-15=0$

Now, to factor the equation, you must find two numbers whose sum is -2 and whose product is -15. Therefore, you have:

$(x-5)(x+3)=0\\x_1=5\\x_2=-3$

7 0

3 years ago

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Help with this please.....<br> 3=c/-11<br> a.33<br> b.-33<br> c.-14<br> d.14

djverab [1.8K]

The answer is b or c

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2 years ago

How much is two thousand three hundred and five-tenths, plus one hundred twenty-five and one-hundredth, plus five thousand ten a

mrs_skeptik [129]

The answer is B.

Hope that helps, if you need any more help, just ask : )

7 0

3 years ago

Read 2 more answers