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3 years ago

PLZ HELP AHHSolve the equation:1)−5x^3+x+2x^3=7−3x^3

1 answer:

7 0

First combine like term

(-5x^3+2x^3) + x = 7- 3x^3

After add -5x^3 and +2x^3 together because it has like term is equal -3x^3

-3x^3 + x = 7-3x^3

Plus -3x^3 from both side

Left x alone you get

X= 7

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Fill in the blank with a constant, so that the resulting expression can be factored as the product of two linear expressions: 2a

Vitek1552 [10]

Answer:

$2ab - 6a + 5b - 15$

Step-by-step explanation:

Given

$2ab - 6a + 5b + \_$

Required

Fill in the gap to produce the product of linear expressions

$2ab - 6a + 5b + \_$

Split to 2

$(2ab - 6a) + (5b + \_)$

Factorize the first bracket

$2a(b - 3) + (5b + \_)$

Represent the _ with X

$2a(b - 3) + (5b + X)$

Factorize the second bracket

$2a(b - 3) + 5(b + \frac{X}{5})$

To result in a linear expression, then the following condition must be satisfied;

$b - 3 = b + \frac{X}{5}$

Subtract b from both sides

$b - b- 3 = b - b+ \frac{X}{5}$

$- 3 = \frac{X}{5}$

Multiply both sides by 5

$- 3 * 5 = \frac{X}{5} * 5$

$X = -15$

Substitute -15 for X in $2a(b - 3) + 5(b + \frac{X}{5})$

$2a(b - 3) + 5(b + \frac{-15}{5})$

$2a(b - 3) + 5(b - \frac{15}{5})$

$2a(b - 3) + 5(b - 3)$

$(2a + 5)(b - 3)$

The two linear expressions are $(2a+ 5)$ and $(b - 3)$

Their product will result in $2ab - 6a + 5b - 15$

<em>Hence, the constant is -15</em>

3 0

3 years ago

Why do equivalent ratios form a straight line when<br> graphed? Explain.

irina1246 [14]

Answer:

The y-values of equivalent ratios increase at the same rate as their x-values. The vertical distance between points is constant, and the horizontal distance between points is constant. This forms a straight line.

Step-by-step explanation:

Equivalent proportions (which are, as a result, equal parts) are two proportions that express a similar connection between numbers. We can make comparable proportions by duplicating or separating both the numerator and denominator of a given proportion by a similar number.

Two ratios that have the same value are called equivalent ratios. To find an equivalent ratio, multiply or divide both quantities by the same number. It is the same process as finding equivalent fractions.

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2 years ago

(1+tanx)/(sinx+cosx)=secx

jek_recluse [69]

$\frac{1+\tan x}{\sin x+\cos x}=\sec x$ is proved