Question

Pls show work! questions on pic

Answer 1

Answer:

a.(10,23)

b.(7,30)

e.(20,20)

Step-by-step explanation:

We are given that

x=Width of garden

y=Length of garden

According to question

$x\geq 5$

$y\geq 20$

Perimeter of rectangle=$2(x+y)$

Where x=Width  of rectangle

y=Length of rectangle

Fencing used =$2(x+y)$

$2(x+y)\leq 80$

First we change inequality  into equality

$x=5$...(1)

$y=20$...(2)

$2(x+y)=80$

$x+y=40$...(3)

Substitute x=0 in equation (3)

$y=40$

Substitute y=0  in equation (3)

$x=40$

Substitute x=0 and y=0 in equation (3)

$2(x+y)\leq 80$

$0\leq 80$

It is true. Therefore, the  shaded region below the line.

$0\geq 5$

$0\geq 20$

These are false equation .Therefore, the shaded region above the line.

Substitute x=5 in equation (3)

$5+y=40$

$y=40-5=35$

Substitute y=20 in equation (3)

$x+20=40$

$x=40-20=20$

Intersection point of equation (1) and (3) is (5,35) and intersect point of equation (2) and (3) is (20,20).

Now,

a.(10,23)

Substitute in

$2(x+y)\leq 80$

$2(10+23)\leq 80$

$66\geq 80$

10>5 and 23>20

it satisfied all inequality.

Hence, it is a solution.

b.(7,30)

7>5

30>20

$2(7+30)=74$

it satisfied all inequality.

Hence, it is a solution.

c.(18,25)

18>5

25>20

$2(18+25)=86>80$

It does not satisfied third inequality

Hence, it is not a solution.

d.(8,35)

8>5

35>20

$2(8+35)=86>80$

It does not satisfied third inequality

Hence, it is not a solution.

e.(20,20)

$2(20+20)=80$

20>5

20=20

it satisfied all inequality.

Hence, it is a solution.