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Savatey [412]
3 years ago
9

One is FPGA and other is ASIC. Budget, power consumption, and speed are the common parameters considered for the selection of th

ese technologies. Suppose, a medium volume production of an image transformation circuit is required. As a Circuit Design team lead, which one of the two IC technologies you will select considering the above given parameters for the design of production of required transformation circuit?
Austerity should be 7 to 8 lines
Computers and Technology
1 answer:
Sati [7]3 years ago
3 0

Answer:

FPGA is an abbreviation for Field Programmable Gate Array while ASICS is an abbreviation of Application Specific Integrated Circuit. By considering the parameters like speed budget and power consumption, I will prefer FPGA as it has short design cycle. FPGA also has a development kit that helps while prototyping. Using FPGA all the required parameters will be provided in satisfied way.

However if one fails while using FPGA the he/she could move towards ASICS.

ASICS on the other hand has following factors:

  • less power consumption
  • less area
  • more speed

ASICS is preferred when one needs larger volume as ASICS has longer design and prototyping cycles.

<h3>I hope it will help you!</h3>

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Answer:  The radio should be tuned to 100. 0 Mhz.

Explanation:

As radio waves are electromagnetic waves, like x-rays, UV rays, and all the wavelengths of visible light, they propagate in the free space at the speed of light: 3. 10⁸ m/s.

At any wave, there is a fixed relationship between the distance travelled by the wave along one cycle (which is called wavelength ) and the speed at which the wave oscillates (which is called the frequency of the wave), with the speed at which the wave propagates, as follows:

λ (wavelength) =  v (speed) / f (frequency)

Replacing by the values, and solving for frequency, we have:

f = 3. 10⁸ m/seg / 3 m = 10⁸ 1/sec = 10⁸ Hz = 100. 0 Mhz

This is the radio channel to which must be tuned in order to listen the station with a wavelength of 3 m, in the FM band.

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3 years ago
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Assume that you have an ArrayList variable named a containing 4 elements, and an object named element that is the correct type t
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Answer:

Option (4) is the correct answer.

Explanation:

In Java programming language ,array collection starts from 0 index location and ends in a size-1 index location. So to access the last elements the user needs to use a[Size-1] statement. so to modify the value of the last location of the array the user needs to use "a[size-1]= element;".

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Another option is invalid because--

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