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erma4kov [3.2K]
3 years ago
7

Pleas help will mark brainlest the choices are at the bottom

Mathematics
2 answers:
dusya [7]3 years ago
6 0

Answer:

1. x is greater than -1

2. x is less than or equal to -1

3. x greater than or equal to -1

4. x is less than -1

Step-by-step explanation:

The filled in dots means it could be equal to, non-filled dots mean it can only be greater or less. When the variable is first, look at the direction of the line

BigorU [14]3 years ago
6 0

You should join my zoom call

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Georgina likes to read during her summer break. The table below shows the number of pages in each book she read last summer and
Burka [1]

The correct answer would be:

B. The number of pages in each book varied more last summer than this summer.

Step-by-step explanation:

I was doing my test and this was the correct answer. Sorry if this is too late for you.! I hope you have a great day.

3 0
3 years ago
Solve 3(x + 2) > x.​
MaRussiya [10]

Answer:

x > - 3

Step-by-step explanation:

Given

3(x + 2) > x  ← distribute left side

3x + 6 > x ( subtract x from both sides )

2x + 6 > 0 ( subtract 6 from both sides )

2x > - 6 ( divide both sides by 2 )

x > - 3

3 0
4 years ago
Read 2 more answers
A-1/6<br> B-2/9<br> C-3/8<br> D-4/7
mash [69]

Answer:

3/8 is terminating decimal number. It's decimal value is 0.375

7 0
3 years ago
A study of one thousand teens found that the number of hours they spend on social networking sites each week is normally distrib
jek_recluse [69]
The z-value that corresponds to a two-tailed 95% confidence interval is z = +/- 1.96. Then the bounds of the confidence interval can be determined as:
Lower bound = mean - z*SD/sqrt(n) = 20 - 1.96*2/sqrt(100) = 20 - 0.12 = 19.88 hours
Upper bound = mean + z*SD/sqrt(n) = 20 + 1.96*2/sqrt(100) = 20 + 0.12 = 20.12 hours
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7 0
3 years ago
Find two complex numbers whose sum is 12 and whose product is 37.​
jeka57 [31]

Answer:

6 ± i and 6 ± i

Step-by-step explanation:

Let x be the first number.

Let y be the second number.

x + y = 12

x × y = 37

Solve for x in the first equation.

x = 12 - y

Put x as 12-y in the second equation and solve for y.

(12- y)y = 37

12y - y² = 37

- y² + 12y - 37 = 0

y = 6 ± i

Put y as 6 ± i in the first equation and solve for x.

x + 6 ± i = 12

x = 12 - 6 ± i

x = 6 ± i

8 0
3 years ago
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