Answer:
One approach to this problem is to obtain the graph for the given equation.
We need to find every intersection those functions have with the axis 'x' and 'y'
starting with g(x)
g(x=0)=0-3, first point (0,-3) it iis the crossing point with 'x' axis
g(x)=0=x-3, second point (3,0) it iis the crossing point with 'y' axis
Lets do the same for f(x)
g(x=0)=0, this leads to the first point (0,0) it iis the crossing point with 'x' axis and also, with the 'y' axis
We dont need to find any other, since always y=x
By plotting we have the attached picture
Now you can see that g(x) differs from its parent function in that is shifted 3 units to the right, and also 3 units down.
Step-by-step explanation:
Multiply the money * the hours
5*7= 35
Answer : $35
Answer:
Mean=50
Step-by-step explanation:
The mean of a probability distribution is a <u>measure of central tendency</u>,and gives information about how the possible values of x are distributed.
The vertical axis measures the probability of finding a specific value of x in the sample. The probability of finding a value near the mean is high (that is why the value of the function that is depicted in the vertical axis, increases as we get closer to the mean=50): this is because the mean is that value of x around which higher probability of occurrence is associated.
Answer:
Option c, A square matrix
Step-by-step explanation:
Given system of linear equations are



Now to find the type of matrix can be formed by using this system
of equations
From the given system of linear equations we can form a matrix
Let A be a matrix
A matrix can be written by
A=co-efficient of x of 1st linear equation co-efficient of y of 1st linear equation constant of 1st terms linear equation
co-efficient of x of 2st linear equation co-efficient of y of 2st linear equation constant of 2st terms linear equation
co-efficient of x of 3st linear equation co-efficient of y of 3st linear equation constant of 3st terms linear equation 
which is a
matrix.
Therefore A can be written as
A= ![\left[\begin{array}{lll}3&-2&-2\\7&3&26\\-1&-11&46\end{array}\right] 3\times 3](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Blll%7D3%26-2%26-2%5C%5C7%263%2626%5C%5C-1%26-11%2646%5Cend%7Barray%7D%5Cright%5D%203%5Ctimes%203)
Matrix "A" is a
matrix so that it has 3 rows and 3 columns
A square matrix has equal rows and equal columns
Since matrix "A" has equal rows and columns Therefore it must be a square matrix
Therefore the given system of linear equation forms a square matrix
Answer: 105 couple tickets and 40 individual tickets
For this I will use the "Graphing Method"
First, we need to set up two equations.
-> Let x be the number of couple tickets.
-> Let y be the number of individual tickets.
-> It is "2x" because a couple means two.
$12x + $8y = $1,580
2x + y = 250
Next, we will graph this.
-> The point at which the two lines intersect is our solution.
-> See attached.
-> x = 105, so 105 couple tickets
-> y = 40, so 40 individual tickets
Have a nice day!
I hope this is what you are looking for, but if not - comment! I will edit and update my answer accordingly.
- Heather