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horrorfan [7]
3 years ago
13

Help please! !!!!! !!!!

Mathematics
2 answers:
labwork [276]3 years ago
8 0

Answer:

A

Step-by-step explanation:

A is more reliable than the others because we  don't know what x is. I am so sorry if this is wrong!!!!! I'm sorry didn't see the select all.

zhannawk [14.2K]3 years ago
4 0

Answer:

I would assume it's all but the second one (earned $60 over the summer=false)

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Please help !!!!!urgent !!!!!Which statement is true according to the diagram ??
DENIUS [597]

Answer:

the second one

8 0
3 years ago
PLS HELP ASAP ILL GIVE BRAINLKEST
Aleonysh [2.5K]

Answer:

To find the slope, use the slope formula. The slope formula is Y2-Y1/X2-X1. Plug in any two points into the equation and solve. I will use (6,4) and (9,6).

6-4/9-6

2/3

The slope of the proportional relationship is 2/3.

Hope this helps! :)

3 0
3 years ago
A 16−oz bottle of parmesan cheese costs $5.78, while an 8−oz bottle costs $3.97. Which is the better buy? Round your answer to t
LUCKY_DIMON [66]

Answer:

The 16-oz bottle of parmesan cheese is the better buy.

Step-by-step explanation:

Even though 8-oz is half the amount of 16-oz, that doesn't mean it's cheaper. Let's find the amount of and 8-oz bottle when a 16-oz bottle is $5.78:

16-oz bottle of parmesan cheese = $5.78

A price of an 8-oz bottle when 16-oz is divided by 2:

16 ÷ 5.78 = $2.76

The original price of the 8-oz bottle should've been $2.76 but it's more expensive due to VAT.

So the 8-oz bottle is more expensive, therefore the 16-oz bottle is the better buy!

8 0
3 years ago
Which of the following is an equation to the tangent line to the graph of (fx) = -2x+4 at 1
Zigmanuir [339]

Answer:

nuts

Step-by-step explanation:

8 0
1 year ago
Find Integrating Fector: <br> ylogy dx + ( x-logy )dy=0
12345 [234]
Rewrite the ODE as

y\log y\,\mathrm dx+(x-\log y)\,\mathrm dy=0\iff y\log y\dfrac{\mathrm dx}{\mathrm dy}+x=\log y
\dfrac{\mathrm dx}{\mathrm dy}=\dfrac1{y\log y}x=\dfrac1y

so that it is now linear in x. An integrating factor would

\mu(y)=\exp\left(\displaystyle\int\frac{\mathrm dy}{y\log y}\right)=e^{\log(\log y)}=\log y

Multiply both sides by \mu(y) to get

\log y\dfrac{\mathrm dx}{\mathrm dy}=\dfrac1yx=\dfrac{\log y}y
\dfrac{\mathrm d}{\mathrm dy}[x\log y]=\dfrac{\log y}y
x\log y=\displaystyle\int\frac{\log y}y\,\mathrm dy
x\log y=\dfrac12\log^2y+C
x=\dfrac12\log y+\dfrac C{\log y}
4 0
4 years ago
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