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Fofino [41]
3 years ago
10

Which inequality is true?

Mathematics
2 answers:
NemiM [27]3 years ago
7 0
It is A the answers is a
babymother [125]3 years ago
3 0

Answer:

i think A

Step-by-step explanation:

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Reduce 25/35 to lowest terms
Sauron [17]

Answer:

 \frac{5}{7}

Step-by-step explanation:

Find the GCD (or HCF) of numerator and denominator

GCD of 25 and 35 is 5

Divide both the numerator and denominator by the GCD

25 ÷ 5

35 ÷ 5

7 0
3 years ago
Read 2 more answers
Which is a quadrilateral that could have one pair of parallel sides and one pair of sides that are not parallel?
Lapatulllka [165]

Answer:

trapezoid.

Step-by-step explanation:

A trapezoid is a convex quadrilateral. A trapezoid has at least on pair of parallel sides. the parallel sides are called bases while the non parallel sides are called legs

Characteristics of a trapezoid

It has 4 vertices and edges

If both pairs of its opposite sides of a trapezoid are parallel, it becomes a parallelogram

Area of a trapezoid = \frac{1}{2} x (sum of the lengths of the parallel sides) x height

Perimeter =  sum of lengths of sides of a trapezoid

8 0
3 years ago
Use the Law of Cosines to find the values of x and y. (PLEASE HELPPP!!!!)
vredina [299]

Answer:

x = 49.8^\circ\\y = 54.6^\circ

Step-by-step explanation:

Kindly refer to the image attached in the answer region for labeling of triangle.

<em>AB </em><em>= 16 </em>

<em>BC </em><em>= 19</em>

<em>AC </em><em>= 15 </em>

\angle ABC = x^\circ\\\angle ACB = y^\circ

We have to find the <em>angles </em><em>x</em> and <em>y</em> i.e. \angle B \text{ and }\angle C.

Formula for <em>cosine rule</em>:

cos B = \dfrac{a^{2}+c^{2}-b^{2}}{2ac}

Where  

<em>a</em> is the side opposite to \angle A,

<em>b</em> is the side opposite to \angle B  and

<em>c</em> is the side opposite to \angle C.

\Rightarrow cos x = \dfrac{19^{2}+16^{2}-15^{2}}{2 \times 19 \times 16}\\\Rightarrow cos x = \dfrac{392}{608} \\\Rightarrow x = 49.8^\circ

Similarly, for finding the value of <em>y:</em>

cos C = \dfrac{a^{2}+b^{2}-c^{2}}{2ab}\\\Rightarrow cos y = \dfrac{19^{2}+15^{2}-16^{2}}{2  \times 19 \times 15}\\\Rightarrow cos y = \dfrac{330}{570}\\\Rightarrow y = 54.6^\circ

Hence, the values are:

x = 49.8^\circ\\y = 54.6^\circ

7 0
3 years ago
Solve for x please help me
Mademuasel [1]

x = 51.98

Step-by-step explanation:

tan 68 = opp/hyp = x/21

or

x = 21×tan68°

= 21(2.475)

= 51.98

3 0
3 years ago
Equivalent Expressions for 6(4t+5)+2
Radda [10]

Answer:

48t + 60

Step-by-step explanation:

hope this helps!!

8 0
3 years ago
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