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Ostrovityanka [42]
3 years ago
14

Sin 300° = 2 sin 150° cos 150° use exact values to show it is true​

Mathematics
1 answer:
strojnjashka [21]3 years ago
8 0

Answer:

see explanation

Step-by-step explanation:

left side = sin300° = - sin60°  and sin60 = \frac{\sqrt{3} }{2}, thus

sin300° = - \frac{\sqrt{3} }{2}

right side

sin150° = sin30° = \frac{1}{2} and

cos150° = - cos30° = - \frac{\sqrt{3} }{2}, thus

2sin150°cos150°

= 2 × \frac{1}{2} × - \frac{\sqrt{3} }{2} = - \frac{\sqrt{3} }{2}

left side = right side ⇒ True

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Answer:

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Step-by-step explanation:

Given

tan\theta = 3

Required

Find

tan\theta + tan(\theta + \pi) + tan(\theta+2\pi)

Calculate tan(\theta + \pi) \ and\ tan(\theta+2\pi)

Using tan rule

tan(\theta + \pi)  = \frac{tan\theta + tan\pi}{1 - tan\theta tan\pi}

So:

tan(\theta + \pi)  = \frac{tan\theta + 0}{1 - tan\theta *0}

tan(\theta + \pi)  = \frac{tan\theta}{1 }

tan(\theta + \pi)  = \tan\theta

tan(\theta+2\pi)

tan(\theta + 2\pi)  = \frac{tan\theta + tan2\pi}{1 - tan\theta tan2\pi}

tan(\theta + 2\pi)  = \frac{tan\theta + 0}{1 - tan\theta *0}

tan(\theta + 2\pi)  = \tan\theta'

'So:

tan\theta + tan(\theta + \pi) + tan(\theta+2\pi) = tan\theta +tan\theta +tan\theta

tan\theta + tan(\theta + \pi) + tan(\theta+2\pi) = 3+3+3

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Complex numbers simplify square roots of negative numbers
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Lets do

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\\ \sf\longmapsto \sqrt{-(10)^2}

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Write in standard form

\\ \sf\longmapsto 10i

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Likurg_2 [28]
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