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Ostrovityanka [42]
3 years ago
14

Sin 300° = 2 sin 150° cos 150° use exact values to show it is true​

Mathematics
1 answer:
strojnjashka [21]3 years ago
8 0

Answer:

see explanation

Step-by-step explanation:

left side = sin300° = - sin60°  and sin60 = \frac{\sqrt{3} }{2}, thus

sin300° = - \frac{\sqrt{3} }{2}

right side

sin150° = sin30° = \frac{1}{2} and

cos150° = - cos30° = - \frac{\sqrt{3} }{2}, thus

2sin150°cos150°

= 2 × \frac{1}{2} × - \frac{\sqrt{3} }{2} = - \frac{\sqrt{3} }{2}

left side = right side ⇒ True

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(1 point) A particle starts at the point P=(−2,−1,3)P=(−2,−1,3) when t=0t=0 and moves along a straight line toward Q=(−4,0,6)Q=(
Ahat [919]

Answer:

The position is given by r(t) =  (-2 -t √14, 1 + √3.5, 3 + 3√3.5)

Step-by-step explanation:

The direction is given by the difference between the starting point and the end point, thus it is (-4,0,6)-(-2,-1,3) = (-2,1,3). The norm of this vector is        √( (-2)²+1²+3²) = √14 = 3.7416 secons

Since the speed is 7 cm/sec, we need to multiply this vector by 7/√14 = √3.5 in order to obtain how much does the particle advance each second.

As a consecuence, it advances (-2,1,3) * √3.5 = (- √14, √3.5, 3 √3.5)

And, as a result, the position after t seconds is given by the function

r(t) = (-2,1,3) + t (-√14, √3.5, 3 √3.5) = (-2 -t √14, 1 + √3.5, 3 + 3√3.5)

8 0
3 years ago
(WILL MARK BRAINLIST)
mezya [45]
I believe the answer is the second one
4 0
2 years ago
If m<BEG = (19x + 3)° and m<EGC = (m<GCB + 4x)°, which of the following statements is true about quadrilateral BEGC? Se
viktelen [127]

Answer:

The sum of all exterior angles of BEGC is equal to 360° ⇒ answer F only

Step-by-step explanation:

* Lets revise some facts about the quadrilateral

- Quadrilateral is a polygon of 4 sides

- The sum of measures of the interior angles of any quadrilateral is 360°

- The sum of measures of the exterior angles of any quadrilateral is 360°

* Lets solve the problem

- DEGC is a quadrilateral

∵ m∠BEG = (19x + 3)°

∵ m∠EGC = (m∠GCB + 4x)°

∵ The sum of the measures of its interior angles is 360°

∴ m∠BEG + m∠EGC + m∠GCB + m∠CBE = 360

∴ (19x + 3) + (m∠GCB + 4x) + m∠GCB + m∠CBE = 360 ⇒ add the like terms

∴ (19x + 4x) + (m∠GCB + m∠GCB) + m∠CBE + 3 = 360 ⇒ -3 from both sides

∴ 23x + 2m∠GCB + m∠CBE = 375

∵ The sum of measures of the exterior angles of any quadrilateral is 360°

∴ The statement in answer F is only true

3 0
3 years ago
On a 16 scale drawing of a bike, one part is 3 inches long. How long will the actual bike part be?
Oksanka [162]
Multiply 16*3 to get 48, the bike is 48 units so 16:1,16/1=16. So the answer would be 16. Hope I helped! 
4 0
3 years ago
Read 2 more answers
Can some one answer this?
Anvisha [2.4K]

Answer:

1. They ate 1/6 of the donuts

2. 2/3

Step-by-step explanation:

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2. 1 1/3=4/3×1/2=4/6=2/3

5 0
2 years ago
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