Sin 300° = 2 sin 150° cos 150° use exact values to show it is true

Mathematics

1 answer:

strojnjashka [21]3 years ago

8 0

Answer:

see explanation

Step-by-step explanation:

left side = sin300° = - sin60° and sin60 = $\frac{\sqrt{3} }{2}$ , thus

sin300° = - $\frac{\sqrt{3} }{2}$

right side

sin150° = sin30° = $\frac{1}{2}$ and

cos150° = - cos30° = - $\frac{\sqrt{3} }{2}$ , thus

2sin150°cos150°

= 2 × $\frac{1}{2}$ × - $\frac{\sqrt{3} }{2}$ = - $\frac{\sqrt{3} }{2}$

left side = right side ⇒ True

You might be interested in

Is -1,4 a solution to the inequality y<2x+5

Sladkaya [172]

Answer:

Step-by-step explanation:

(x, y)

(-1, 4)

4 < 2(-1) + 5

4 < -2 + 5

4 < 3

not true

7 0

3 years ago

The graph of a line and an exponential can intersect twice, once or not at all. Describe the possible number of intersections fo

Katyanochek1 [597]

Answer:

c) parabola and circle: 0, 1, 2, 3, 4 times

d) parabola and hyperbola: 1, 2, 3 times

Step-by-step explanation:

c. A parabola can miss a circle, be tangent to it in 1 or 2 places, intersect it 2 places and be tangent at a 3rd, or intersect in 4 places.

d. A parabola must intersect a hyperbola in at least one place, but cannot intersect in more than 3 places. If the parabola is tangent to the hyperbola, the number of intersections will be 2.

If the parabola or the hyperbola are "off-axis", then the number of intersections may be 0 or 4 as well. Those cases seem to be excluded in this problem statement.