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3 years ago

What is the scale factor of the dilation shown?

Mathematics

1 answer:

artcher [175]3 years ago

5 0

Answer:

sorry I dont see the eqation I would help I just need to look at it - sorry (>-<)

Step-by-step explanation:

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a total of 408 tickets were sold for the school play. They were either adult tickets or student tickets. The number of students

Mama L [17]

Given Situation:
=> There are 408 total of ticket sold for a school play
=> 3 times of the tickets are sold to students compare to the adults
=> So the ratio of the given situation is 1 : 3
=> Now, 1 + 3 = 4
Since, we need 4 parts, let’s divide 408 by 4
=> 408 / 4 = 102 – the number of tickets for adults
=> 102 x 3 = 306 – the number of tickets for students
=> 102 : 306

4 0

3 years ago

Which is the longer trip from Earth, a one-way trip to Mars or a round-trip to Venus?

dimulka [17.4K]

if a trip from earth to mars, is 97/186=.52150

and a trip from earth to venus is 0.2774(now we have to times it by 2 since its a roundtrip),

we get .5548 we can clearly see that .5548>.52150

So roundtrip venus

6 0

4 years ago

Read 2 more answers

How to solve question 3

Temka [501]

I would say screw it and use the calculator anyway

7 0

3 years ago

5 root 12 + 4 root 12 - 3 root 18 +2root 75

Ratling [72]

Answer: 28 $\sqrt{3}$ - 9 $\sqrt{2}$

Step-by-step explanation:

5 $\sqrt{12}$ + 4 $\sqrt{12}$ - 3 $\sqrt{18}$ + 2 $\sqrt{75}$

5 $\sqrt{12}$ + 4 $\sqrt{12}$ can be added together since they have the same radical, they will be treated as if you have 5 apples + 4 apples , which will be 9 apples

Therefore we have

9 $\sqrt{12}$ - 3 $\sqrt{18}$ + 2 $\sqrt{75}$

$\sqrt{12}$ = $\sqrt{4}$ X $\sqrt{3}$ = 2 $\sqrt{3}$

$\sqrt{18}$ = $\sqrt{9}$ X $\sqrt{2}$ = 3 $\sqrt{2}$

$\sqrt{75}$ = $\sqrt{25}$ X $\sqrt{3}$ = 5 $\sqrt{3}$

Returning them back into the expression , we have

9(2 $\sqrt{3}$ ) - 3(3 $\sqrt{2}$ ) + 2 (5 $\sqrt{3}$ )

⇒ 18 $\sqrt{3}$ - 9 $\sqrt{2}$ + 10 $\sqrt{3}$

= 28 $\sqrt{3}$ - 9 $\sqrt{2}$

3 0

4 years ago

Look at the formula for the area of a circle below. . . A = 3.14(pi)r2 . . Which of the following equations can be used to solve

zaharov [31]

You did not include the equations that you want to assess whether they can be used to solve for the radius (r). Likely, the equation of the circumference, C = 2*Pi*r is included, if so => r = C / (2*Pi). If you round Pi to 3.14, the equation may be written r = C / 6.28.

6 0

3 years ago