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3 years ago

What is the scale factor of the dilation shown?

Mathematics

1 answer:

artcher [175]3 years ago

5 0

Answer:

sorry I dont see the eqation I would help I just need to look at it - sorry (>-<)

Step-by-step explanation:

You might be interested in

The equation of line m is 3x−5y=−4

vaieri [72.5K]

Slope of this line, -5y = -3x - 4
y = 3/5x + 4/5
So, slope of line which is perpendicular = -5/3 [reciprocal & opposite ]

In short, Your Answer would be -5/3

Hope this helps!

4 0

4 years ago

Standard Error from a Formula and a Bootstrap Distribution Sample A has a count of 30 successes with and Sample B has a count of

tia_tia [17]

Answer:

Using a formula, the standard error is: 0.052

Using bootstrap, the standard error is: 0.050

Comparison:

The calculated standard error using the formula is greater than the standard error using bootstrap

Step-by-step explanation:

Given

Sample A Sample B

$x_A = 30$ $x_B = 50$

$n_A = 100$ $n_B =250$

Solving (a): Standard error using formula

First, calculate the proportion of A

$p_A = \frac{x_A}{n_A}$

$p_A = \frac{30}{100}$

$p_A = 0.30$

The proportion of B

$p_B = \frac{x_B}{n_B}$

$p_B = \frac{50}{250}$

$p_B = 0.20$

The standard error is:

$SE_{p_A-p_B} = \sqrt{\frac{p_A * (1 - p_A)}{n_A} + \frac{p_A * (1 - p_B)}{n_B}}$

$SE_{p_A-p_B} = \sqrt{\frac{0.30 * (1 - 0.30)}{100} + \frac{0.20* (1 - 0.20)}{250}}$

$SE_{p_A-p_B} = \sqrt{\frac{0.30 * 0.70}{100} + \frac{0.20* 0.80}{250}}$

$SE_{p_A-p_B} = \sqrt{\frac{0.21}{100} + \frac{0.16}{250}}$

$SE_{p_A-p_B} = \sqrt{0.0021+ 0.00064}$

$SE_{p_A-p_B} = \sqrt{0.00274}$

$SE_{p_A-p_B} = 0.052$

Solving (a): Standard error using bootstrapping.

Following the below steps.

Open Statkey
Under Randomization Hypothesis Tests, select Test for Difference in Proportions
Click on Edit data, enter the appropriate data
Click on ok to generate samples
Click on Generate 1000 samples ---- <em>see attachment for the generated data</em>

From the randomization sample, we have:

Sample A Sample B

$x_A = 23$ $x_B = 57$

$n_A = 100$ $n_B =250$

$p_A = 0.230$ $p_A = 0.228$

So, we have:

$SE_{p_A-p_B} = \sqrt{\frac{p_A * (1 - p_A)}{n_A} + \frac{p_A * (1 - p_B)}{n_B}}$

$SE_{p_A-p_B} = \sqrt{\frac{0.23 * (1 - 0.23)}{100} + \frac{0.228* (1 - 0.228)}{250}}$

$SE_{p_A-p_B} = \sqrt{\frac{0.1771}{100} + \frac{0.176016}{250}}$

$SE_{p_A-p_B} = \sqrt{0.001771 + 0.000704064}$

$SE_{p_A-p_B} = \sqrt{0.002475064}$

$SE_{p_A-p_B} = 0.050$

5 0

3 years ago

Explain please, I’ve been having trouble with this question

GuDViN [60]

Step-by-step explanation:

I didn't need the other angles, but right of the bat you can tell it's two right triangles back to back.

<em>y </em> has to be 90° , as you have noticed they already gave you 70° on the right side of the shape meaning if you were to add 90 which is why plus 70 what would that give you? 160.

the total interior for a triangles angles has to be 180°. if you do the math 180 - 160 you get the leftover 20° for x.

I suck at explaining stuff, hope this helps

7 0

2 years ago

1. Two or more linear inequalities in the same variable x and y are called

Serjik [45]

Step-by-step explanation:

A. linear equation
D. None of the above
B. Boundary line Broken line
A solid line
6.sorry

3 0

3 years ago

Need Help with this question

Fantom [35]

82
The sum of the three angles is 180. One is given and the other we can figure out because it forms a straight line (180) with the angle to the left outside. The outside angle is 117, so 180-117 is 63.
So then add up the 3 angles in the triangle
63+35+y=180
y= 82

3 0

3 years ago