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Juliette [100K]
3 years ago
5

Do this correctly, step per step. will mark BRAINLIEST

Mathematics
1 answer:
mestny [16]3 years ago
7 0

Answer:

The y^12 is supposed to be on top.

Step-by-step explanation:

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Reduce this fraction to lowest terms. 27/45<br><br> A.3/5<br> B.9/15<br> C.5/9
Mama L [17]
The simplest form for this fraction is (A)
You divide both the numerator and denominator by 9, you will get 3/5.
so the answer is A.
5 0
3 years ago
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Svetradugi [14.3K]

Answer:

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3 years ago
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Find the area of each regular polygon. Round your answer to the nearest tenth if necessary.
tatuchka [14]

*I am assuming that the hexagons in all questions are regular and the triangle in (24) is equilateral*

(21)

Area of a Regular Hexagon: \frac{3\sqrt{3}}{2}(side)^{2} = \frac{3\sqrt{3}}{2}*(\frac{20\sqrt{3} }{3} )^{2} =200\sqrt{3} square units

(22)

Similar to (21)

Area = 216\sqrt{3} square units

(23)

For this case, we will have to consider the relation between the side and inradius of the hexagon. Since, a hexagon is basically a combination of six equilateral triangles, the inradius of the hexagon is basically the altitude of one of the six equilateral triangles. The relation between altitude of an equilateral triangle and its side is given by:

altitude=\frac{\sqrt{3}}{2}*side

side = \frac{36}{\sqrt{3}}

Hence, area of the hexagon will be: 648\sqrt{3} square units

(24)

Given is the inradius of an equilateral triangle.

Inradius = \frac{\sqrt{3}}{6}*side

Substituting the value of inradius and calculating the length of the side of the equilateral triangle:

Side = 16 units

Area of equilateral triangle = \frac{\sqrt{3}}{4}*(side)^{2} = \frac{\sqrt{3}}{4}*256 = 64\sqrt{3} square units

4 0
3 years ago
A sum of money when invested for a definite period at r% simple interest will yield an interest of rm80 .using the same interest
maks197457 [2]
The invest could probably be maybe 8% for a question
7 0
3 years ago
What is the domain of f(x) = (x + 2)2 – 1?
larisa [96]

Simplify

\\ \tt\Rrightarrow f(x)=(x+2)^2-1

\\ \tt\Rrightarrow f(x)=x^2+4x+2-1

\\ \tt\Rrightarrow f(x)=x^2+4x+1

The Domain is set of all real numbers

\\ \tt\Rrightarrow Domain\in R

4 0
2 years ago
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