The sum of three consecutive numbers is 57. What is the largest of these numbers?
2 answers:
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The length of cuboid is 16 cm and breadth of cuboid is 4 cm.
<h3>How to find the Surface Area of Cuboid?</h3>A cuboid has 6 rectangular faces. To find the surface area of a cuboid, add the areas of all 6 faces. We can also label the length (L), Breadth (B), and Height (H) of the cuboid and use the formula, SA=2 x ( LB + BH + HL ) , to find the surface area.
Here, We have given that height of the cuboid is 5cm.
Let length of the cuboid = X cm
so, the breadth of the cuboid = cm
also, we have given that total surface area is 328 cm²
Now, put all the values in the formula of Surface Area (SA):
SA = 2 x ( LB + BH + HL )
SA = 2 x ( X²/4 + 5X/4 + 5X )
SA = 2 x ( ( X² + 5X + 20X) / 4 )
SA = ( X² + 5X + 20X ) / 2
X² + 5X + 20X = 328 x 2
X² + 25X = 656
X² + 25X - 656 = 0
using Quadratic Formula: see the attached figure for the formula.
here Discriminant D = b² - 4ac
D = 625 - 4(-656)
D = 3249
on putting value of D or b² - 4ac in the formula we get
X = ( -25 + 57 ) / 2 and ( -25 - 57 ) /2
length can not be negative so we eliminate the second answer.
now, X = 16 cm
breadth = X /4 = 4 cm
Hence, The length of cuboid is 16 cm and breadth of cuboid is 4 cm.
Learn more about " Quadratic Formula " from here: brainly.com/question/2615966
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Answer:
Monday he walked
Wednesday he walked
Friday he walked
Step-by-step explanation:
Given Mason walked on Monday, Wednesday and Friday. These distances were six-eights mile, one-fourth mile, and one-sixth mile. He did not walk the farthest on Monday. He walked less on Friday than Monday. we have to find how far he walked each day.
distances are that are 0.75, 0.25 and 0.17 respectively.
Now, he didn't walk farthest on Monday and also walked less on Friday than Monday.
∴ Less distance travelled is which is on friday and then
on monday.
Rest distance which is on wednesday.
Hence, Monday he walked
Wednesday he walked
Friday he walked