4 x 1 thousand (1000) = 4000
21 x 1 ten (10) = 210
4000
+ 210
---------
4210
=4210 (four thousand-two hundred and ten
Answer:
y_c = 2 + 10*x
Step-by-step explanation:
Given:
y'' = 0
Find:
- The solution to ODE such that y(0) = 2, y'(0) = 10
Solution:
- Assuming a solution y = Ce^(mt)
So, y' = C*me^(mt)
y'' = C*m^2e^(mt)
- Back substitute into given ODE, we get:
y'' = C*m^2e^(mt) = 0
e^(mt) can not be equal to zero
- Hence, m^2 = 0
m = 0 , 0 - (repeated roots)
- The complimentary function for repeated roots is:
y_c = (C1 + C2*x)*e^(m*t)
y_c = C1 + C2*x
- Evaluate @ y(0) = 2
2 = C1 + C2*0
C1 = 2
-Evaluate @ y'(0) = 10
y'(t) = C2 = 10
Hence, y_c = 2 + 10*x
Answer:
Starcraft
a) Probability of losing at most 2 games = 33%
b) Probability of winning at least 4 games = 67%
Step-by-step explanation:
a) To lose 2 out of 6 games, the probability is 2/6 x 100 = 33.333%
b) To win at least 4 games out of 6, the probability is 4/6 x 100 = 66.667%
c) Since Serral is playing 6 games, for her to lose at most 2 of the games is described as a probability in this form 2/6 x 100. This shows the chance that 2 of the games out of 6 could be lost by Serral. On the other hand, the probability of Serral winning at least 4 of the 6 games is given as 4/6 x 100. It implies that there is a chance, 4 out of 6, that Serral would win the game.
Answer:
323232
Step-by-step explanation:
Calculators are good for stuff like this
