Question

What are the coordinates of the center of the hyperbola with equation (x-2)^2/4^2-(y+3)^2/5^2=1

Answer 1

Answer: (6, -3)

(x^2-4x+4)/16-(y^2+6y+9)/25 = 1

x = 6

y = -3

6^2 = 36

4 * 6 = 24

36 - 24 = 12

12 + 4 = 16

16/16 = 1

-3^2 = 9

6 * -3 = -18

9 - 18 = -9

-9 + 9 = 0

0/25 = 0

1 - 0 = 1

I really hope this helped, at least a little bit.