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otez555 [7]
3 years ago
10

Which number line represents the solution to the inequality 225x + 400 ≥ 2200?

Mathematics
1 answer:
Elis [28]3 years ago
8 0

Answer:

I think it's A

Step-by-step explanation:

225x + 400 ≥ 2200

225x ≥ 1800

x ≥ 8

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Andrea bought tacos from a food truck and left a 25%tip of 2.00
disa [49]

Answer:

8.00$

Step-by-step explanation:

if you think about it. In a dollar theres 4 quarters. 100 divided equally is 25 so that is 1/4 of the amount. 2x4 is 8.

7 0
3 years ago
What is the equation in point -slope form. of the line passing through (0, 5) and (-2,11)
Ksivusya [100]
First, you need to find the slope of the line. You can use this with the slope formula, \frac{y_{2} - y_{1}}{x_{2} - x_{1}}, where the x's and y's are the given coordinates.

\frac{y_{2} - y_{1}}{x_{2} - x_{1}}   Plug in the coordinates
\frac{11 - 5}{-2 - 0}   Subtract
\frac{6}{-2}   Divide
-3

Now, plug the slope (m) and one pair of coordinates, I'll use (-2, 11), into point-slope form, y - y_{1} = m (x - x_{1}).

y - y_{1} = m (x - x_{1})   Plug in the values
y - 11 = -3 (x - (-2)   Cancel out the double negative
y - 11 = -3 (x + 2)


5 0
3 years ago
A small can if cat food weights 0.5 pounds . Millie's cat ate 0.3 can of food. How much food did mollies cat eat?
Alex
68.04 grams
Since it's half a pound you would need to find thirty percent of half a pound

6 0
4 years ago
Please help im so lost right now
Ne4ueva [31]
I feel like it x=89 degrees....Becuase that is what i got...
7 0
3 years ago
A store is selling 5 types of hard candies: cherry, strawberry, orange, lemon and pineapple. How many ways are there to choose:(
Volgvan

Answer:

The number of ways of selecting of n items form r different items =^{(n+r-1)}C_{(r-1)}

A store is selling 5 types of hard candies: cherry, strawberry, orange, lemon and pineapple.

A) How many ways are there to choose 32 candies?

So, n = no. of items = 32

r = no. of types of items = 5

So, No. of ways to choose 32 candies = ^{(32+5-1)}C_{(5-1)}

                                                               = ^{36}C_{4}

                                                                 = \frac{36!}{4!(36-4)!}

                                                                 = 58905

So, No. of ways to choose 32 candies is 58905

B)32 candies with at least a piece of each flavor?

Out of 32 you choose 5 candies of different types

So, Remaining candies = 32 - 5 = 27

So, No. of ways to choose 27 candies = ^{(27+5-1)}C_{(5-1)}

                                                               = ^{31}C_{4}

                                                                 = \frac{31!}{4!(31-4)!}

                                                                 = 31465

So, No. of ways to choose 32 candies with at least a piece of each flavor is 31465

C) 32 candies with at least 4 cherry and at least 6 lemon?

So, you already choose 6+4= 10

So, remaining candies = 32-10 = 22

So, No. of ways to choose 22 candies = ^{(22+5-1)}C_{(5-1)}

                                                               = ^{26}C_{4}

                                                                 = \frac{26!}{4!(26-4)!}

                                                                 = 14950

Hence No. of ways to choose 32 candies with at least 4 cherry and at least 6 lemon is 14950

8 0
4 years ago
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