Ask question

Ask question

All categories

2 years ago

11

Find the largest possible revenue from the demand equation "Q= -2p + 1000

1 answer:

Mariana [72]2 years ago

3 0

Revenue=quantity x price= (-2p+1000) (p)= -2p^2+1000p
The maximum revenue will occur when the first derivative is zero so when 2(-2p)+1000=0;p=250
Which generates 125,000 in revenue
Try prices of 245 and 255 and you will see they both are less than 250 thereby proving the max revenue is 250

You might be interested in

Need help ASAP giving 25 points

Kruka [31]

Answer:

63in. 2

Step-by-step explanation:

7 0

3 years ago

Simplify 4(5x - 6) - 4(2x + 1)<br><br> 12x - 5<br> 12x - 20<br> 12x - 28

Harman [31]

First use distributive property:
4(5x - 6) - 4(2x + 1)
20x - 24 - 8x - 4
Then add like terms:
12x - 28

7 0

2 years ago

Read 2 more answers

What is the value of y? y = 30 y = 50 y = 110 y = 130

____ [38]

Answer:

The value of y is 50.

Step-by-step explanation:

It is 50 because it is the exact same as the first degree.

And at least give a picture of problem please so we can solve it easily!! hope you next time!!

8 0

1 year ago

The notation f:S→T denotes that f is a function, also called a map , defined on all of a set S and whose outputs lie in a set T

AnnyKZ [126]

Answer:

There are many. Two examples are

$f(x) = x, \\f(x) = x^3$

Step-by-step explanation:

There are many examples. The simplest is

1 -

$f(x) = x$

It is trivial that

$\text{if \,\,\,\,} f(x) = f(y) \,\,\,\,\,\text{then} \,\,\,\,\, x=y$

2 -

$f(x) = x^3$

That function is injective as well.

$\text{if \,\,\,\,} x^3 = y^3 \,\,\,\,\,\text{then} \,\,\,\,\, x=y$

An example of a function that is NOT injective is

$f(x) = x^2$

Notice that

$f(-2) = (-2)^2 = 2^2 = 4$

4 0

3 years ago

At 6 a.m. the temperature was -9oF. By 11 a.m., the temperature had increased 34oF. What was the temperature at 11 a.m.?

lesantik [10]

The resulting temperature was 25oF.

7 0

2 years ago