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valentina_108 [34]
2 years ago
10

X) sec’A + cosec?AsecA. cosecA​

Mathematics
1 answer:
VikaD [51]2 years ago
3 0

Answer:

(Sin A + Cos A)/Sin A. Cos A

Step-by-step explanation:

As we know

Sec A = 1/Cos A

and Cosec A = 1/Sin A

Given Equation

Sec A + Cosec A

Substituting the given values, we get -

1/cos A + 1/Sin A

(Sin A + Cos A)/Sin A. Cos A

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Read 2 more answers
Differentiating a Logarithmic Function in Exercise, find the derivative of the function. See Examples 1, 2, 3, and 4.
Tasya [4]

Answer:

\frac{dy}{dx}=-[(\frac{5x+24}{36x-6x^2})]

Step-by-step explanation:

Given function:

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we know

\ln(\frac{A}{B}) = ln(A) - ln(B)

thus,

y = \ln((6 - x)^{\frac{3}{2}}) - \ln(x^{\frac{2}{3}})

or

also,

ln(Aⁿ) = n × ln(A)

thus,

y = (\frac{3}{2})\times\ln(6 - x) - (\frac{2}{3})\times\ln(x)

therefore,

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or

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or

\frac{dy}{dx}=-[(\frac{3(3x)+2\times2(6-x)}{2(6-x)\times(3x)})]

or

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