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Katyanochek1 [597]
3 years ago
7

Axis of symmetry of h=-16t^2+20t+6​

Mathematics
1 answer:
eimsori [14]3 years ago
7 0

Answer:

t = \frac{5}{8}

Step-by-step explanation:

Given a parabola in standard form : ax² + bx + c : a ≠ 0

Then the axis of symmetry is

x = - \frac{b}{2a}

h = - 16t² + 20t + 6 is in standard form

with a = - 16 and b = 20, hence

t = - \frac{20}{-32} = \frac{5}{8} ← axis of symmetry

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