Question

Axis of symmetry of h=-16t^2+20t+6​

Answer 1

Answer:

t = $\frac{5}{8}$

Step-by-step explanation:

Given a parabola in standard form : ax² + bx + c : a ≠ 0

Then the axis of symmetry is

x = - $\frac{b}{2a}$

h = - 16t² + 20t + 6 is in standard form

with a = - 16 and b = 20, hence

t = - $\frac{20}{-32}$ = $\frac{5}{8}$ ← axis of symmetry