<span>Ruth's self-esteem and self-confidence all will be at normal levels.
When a teen reaches puberty she has no direct effect on self-esteem or confidence. The kind of looks which changes at this stage can make a person to lose self-esteem.
The best way is a person to take care of herself or himself. Puberty stage is when a girl starts to see some hair in the armpits and on the private parts. Even the voice changes.</span>
Marine fossils are only in places where the ocean used to be, millions of years ago. Then the marine life that died, its dead bodies remained there to later on became fossils...
Answer:
The answer is below
Explanation:
The half life of a substance is the time required by that substance to reduce to half of its initial value. The half life is calculated using the formula:
![N(t)=N_o(\frac{1}{2} )^\frac{t}{t_\frac{1}{2} } \\\\where\ N(t)=quantity\ of\ substance \ remaining, N_o=initial\ quantity\\of\ substance, t=time\ and \ t_\frac{1}{2}=half\ life\ of\ substance](https://tex.z-dn.net/?f=N%28t%29%3DN_o%28%5Cfrac%7B1%7D%7B2%7D%20%29%5E%5Cfrac%7Bt%7D%7Bt_%5Cfrac%7B1%7D%7B2%7D%20%7D%20%5C%5C%5C%5Cwhere%5C%20N%28t%29%3Dquantity%5C%20of%5C%20substance%20%5C%20remaining%2C%20N_o%3Dinitial%5C%20quantity%5C%5Cof%5C%20substance%2C%20t%3Dtime%5C%20and%20%5C%20t_%5Cfrac%7B1%7D%7B2%7D%3Dhalf%5C%20life%5C%20of%5C%20substance)
Given that t = 87 years, half life = 29 years, therefore the quantity of strontium-90 left is:
![N(t)=N_o(\frac{1}{2} )^\frac{87}{29} \\\\N(t)=N_o(\frac{1}{2} )^\frac{t}{t_\frac{1}{2} } \\\\N(t)=N_o(\frac{1}{2} )^3\\\\N(t)=\frac{1}{8} N_o](https://tex.z-dn.net/?f=N%28t%29%3DN_o%28%5Cfrac%7B1%7D%7B2%7D%20%29%5E%5Cfrac%7B87%7D%7B29%7D%20%5C%5C%5C%5CN%28t%29%3DN_o%28%5Cfrac%7B1%7D%7B2%7D%20%29%5E%5Cfrac%7Bt%7D%7Bt_%5Cfrac%7B1%7D%7B2%7D%20%7D%20%5C%5C%5C%5CN%28t%29%3DN_o%28%5Cfrac%7B1%7D%7B2%7D%20%29%5E3%5C%5C%5C%5CN%28t%29%3D%5Cfrac%7B1%7D%7B8%7D%20N_o)
That is one-eight of Strontium 90 would be left after 87 years
Sugar molecules (i.e. glucose) are broken down into simpler molecules such as pyruvate. Pyruvate, in the presence of oxygen will be converted to Acetyl-CoA and it will enter the tricarboxylic acid cycle wherein it will produce series of reducing compounds such as NADH and FADH. These reducing compounds are then processed in the electron transport chain and oxidized, and the energy released in the oxidation of NADH and FADH is transferred to the high energy phosphate bond of adenosine triphosphate or ATP.