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Elena L [17]
2 years ago
12

Find the minimum value of the parabola

rmula1" title=" y = x^{2} + 3x + 2" alt=" y = x^{2} + 3x + 2" align="absmiddle" class="latex-formula">
Mathematics
1 answer:
tigry1 [53]2 years ago
8 0
Y=2
X= -3/2
Vertex= -3/2 and -1/4
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Answer:

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Step-by-step explanation:

Since you are given a set of options to choose from, a very simple way to find the zero of the polynomial is by simply plugging each  value from the options and seeing which of them gives the answer 0.

f(x) = 2x^3+x^2-25x+12\\

Using all the options:

a)\,f(-3) = 2(-3)^3+(-3)^2-25(-3)+12\\f(-3) = 42\\\\b)\,f(4) = 2(4)^3+(4)^2-25(4)+12\\f(4) = 56\\\\c)\,f(-4) = 2(-4)^3+(-4)^2-25(-4)+12\\f(-4) = 0\\\\d)\,f(12) = 2(12)^3+(12)^2-25(12)+12\\f(12) = 3312

Now we know that at x = -4 the value of the polynomial f(x) is 0. hence

b) x=-4 is another zero of the polynomial

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Read 2 more answers
Help!!!! 20 points!!!!!!’
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