Answer:
The confidence limits for the proportion that plan to vote for the Democratic incumbent are 0.725 and 0.775.
Step-by-step explanation:
In a sample with a number n of people surveyed with a probability of a success of
, and a confidence level of
, we have the following confidence interval of proportions.

In which
z is the zscore that has a pvalue of
.
Of the 500 surveyed, 350 said they were going to vote for the Democratic incumbent.
This means that 
80% confidence level
So
, z is the value of Z that has a pvalue of
, so
.
The lower limit of this interval is:

The upper limit of this interval is:

The confidence limits for the proportion that plan to vote for the Democratic incumbent are 0.725 and 0.775.
The answer is: " x < -3 " .
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Explanation:
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Given:
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" 9(2x + 1) < 9x – 18 " ;
First , factor out a "9" in the expression on the right-hand side of the inequality:
9x – 18 = 9(x – 2) ;
and rewrite the inequality:
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9(2x + 1) < 9(x – 2) ;
Now, divide EACH SIDE of the inequality by "9" ;
[9(2x + 1)] / 9 < [9(x – 2)] / 9 ;
to get:
2x + 1 < x – 2 ;
Now, subtract "x" and add "2" to each side of the inequality:
2x + 1 – x + 2 < x – 2 – x + 2 ;
to get:
x + 3 < 0 ;
Subtract "3" from EACH SIDE ;
x + 3 – 3 < 0 – 3 ;
to get:
" x < -3 " .
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An easy way to solve fraction problems like this is to make each fraction have the same denominator. Since he has $100, the denominator will be 100.
2/10=?/100 10*10=100 1*10=20 20/100 of his money he wants to spend on video games
55/100 already has 100 as its denominator, so he wants to spend 55/100 on a skateboard.
3/10=?/100 10*10=100 3*10=100 30/100 is how much he wants to spend on comic books.
Add all of the fractions together to see how much he wants to spend and if he has enough.
20/100+55/100+30/100=105/100
He wants to spend $105, which is $5 more than he has.
Answer:
The traditional scale consists of two plates or bowls suspended at equal distances from a fulcrum. One plate holds an object of unknown mass (or weight), while known masses are added to the other plate until static equilibrium is achieved and the plates level off, which happens when the masses on the two plates are equal. The perfect scale rests at neutral. A