Answer:
1/8 or 0.125
Step-by-step explanation:
Let x be the length of the sides of the square ABCD.
Therefore, the length of CN and CM is x/2.
The area of the triangle MCN is:

The area of the square ABCD is:

Thus, the probability that a random point lies in the triangle MCN is:

The probability that the point will lie in the triangle MCN is 1/8 or 0.125.
Answer:
9/7
Step-by-step explanation:
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Answer:
I think it's 30
Step-by-step explanation:
I took it as reflection of light..or ig it has same idea
Answer:
Should be 82% sorry if I'm wrong have a amazing day