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Levart [38]
3 years ago
5

-1/3,-1,-3,-9,-27 what's the next number pattern

Mathematics
2 answers:
Fed [463]3 years ago
8 0

-81 is the answer because you need to multiply 3 to each number to get the next


elena-s [515]3 years ago
4 0
-27x3 = -81 :) hope this helped you out
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b. If the tank is then filled to capacity, how many half-gallon bottles can be filled with the water in the tank
d1i1m1o1n [39]

Step-by-step explanation:

if the tank is filled with a cap on field to capacity how many half gallons of bottles are filled it will be about well first you have to think how much is half a gallon and it's a half of a gallon is 2 quarts how big is the tank that's what you want to know if you want to fill it up cuz I haven't gotten this 2 quarts tell me how big is the tank

5 0
3 years ago
Brenda has money invested in Esti Transport. She owns two par value $1,000 bonds issued by Esti Transport, which currently sells
Debora [2.8K]

Answer:

B is the the answer but I'm not sure

7 0
3 years ago
Describe how both the Rational Root Theorem and Descartes’ Rules of Signs help you to find the zeros of a polynomial? Give me an
MrRa [10]

Answer:

Step-by-step explanation:

Rational Root Theorem: If the polynomial

P(x) = a n x n + a n – 1 x n – 1 + ... + a 2 x 2 + a 1 x + a 0

has any rational roots, then they must be of the form of (factors of a0/factors of an).

Example: F(x) = 4x² + 5x +2

If this polynomial has any rational roots, then they must be (factors of 2)/(factors of 4), so (±1, ±2)/(±1, ±2, ±4). So if this polynomial has any rational roots, they must be either: ±1, ±1/2, ±1/4, or ±2. Notice that this polynomial doesn't have to have any rational roots, but if it does, then the roots must fit the Rational Root Theorem.

Descartes' Rules of Signs:

a). In a polynomial, how many time the sign changes is how many positive roots the polynomial will have.

Example: 5x³ + 6x² - 2x - 1

In this expression, the sign only changed once, between 6x² and 2x, so it will only have one positive root.

Example 2: 6x³ - 4x² + x - 6

In this expression, the sign changed 3 times (remember there is a invisible "+" sign before the 6x³), so it will have 3 positive roots.

b). In a polynomial, if you plug in "-x" for all "x", then how many times the new polynomial changes sign is how many negative roots the old polynomial have.

Example: 5x³ + 6x² - 2x - 1.

If we plug in "-x" for all "x", then we get 5(-x)³ + 6(-x)² - 2(-x) -1, which simplifies to -5x³ + 6x² + 2x -1. In this new expression, the sign changed twice, so we have two negative roots for the expression. Notice how we got one positive root the first time and two negative roots the second time, and 1 + 2 = 3. The Fundamental Theorem of Algebra states that for a nth degree polynomial, it will have n complex roots. The polynomial we worked with was a 3rd degree polynomial, and we got 1 + 2 = 3 roots in the end.

4 0
3 years ago
Twelve of the 40 cars pulled by the locomotive were tankers.
quester [9]
12 are tankesr
40 cars total
12/40
12/40=6/20=3/10

3/10=tankders
10/10-3/10=7/10
7/10=70/100=70%
70% wern't tankser
3 0
3 years ago
PLEASE HELP ASAPPPPPPPPPPPPPPP
Andru [333]

Answers:

  • a) -3
  • b)  7/3
  • c)  -1/2
  • d)  1/11
  • e)  undefined
  • f) 0
  • d)  2/3

========================================================

Explanation:

If the original slope is a/b, then the perpendicular slope is -b/a

We flip the fraction and we flip the sign from positive to negative, or vice versa.

As an example, the slope 1/3 flips its fraction to 3/1 or just 3. Then we flip the sign to -3. So if the original slope is 1/3, then its perpendicular counterpart is -3.

Notice how the two slopes multiply to -1

(1/3)*(-3) = -1

This applies to any pair of perpendicular lines such that neither line is horizontal and neither line is vertical either.

------------------------

If the original slope is some whole number, then rewrite it as a fraction over 1

Example: 2 becomes 2/1

That way we can flip the fraction and the sign

-------------------------

If we had an original slope of 0, then it's the same as 0/1

Flipping the fraction leads to 1/0, but that's undefined. We cannot divide by zero. So that explains the answer to part e).

Going in reverse of this process, any line with undefined slope will be perpendicular to lines of slope 0.

horizontal lines have slope of 0

vertical lines have undefined slopes

-------------------------

For part g), you'll need to convert from a mixed number to an improper fraction

Use this formula

a & b/c = (a*c + b)/c

So this means,

1 & 1/2 = (1*2 + 1)/2 = 3/2

which leads to

-1 & 1/2 = -3/2

Then applying the rule "flip the fraction flip the sign" gets us from -3/2 to 2/3.

4 0
2 years ago
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