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const2013 [10]
3 years ago
11

PLEASE ASAP ILL GIVE BRAINLIEST.

Mathematics
2 answers:
Solnce55 [7]3 years ago
6 0
3rd one I did this once and I got it correct
arsen [322]3 years ago
4 0

Answer:

the correct answer is option C

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Pls answer I need help majorly, don't answer if you don't know and if you want points tell me in the COMMENTS and I'll make a th
BlackZzzverrR [31]

Answer:

30

Step-by-step explanation:

I am serious because they are the same angle. Can someone help me with my question plz

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3 years ago
PLEASE HELP I really need help with it:/
Luda [366]

Answer:

  • q = 14

Step-by-step explanation:

<u>We know that:</u>

  • 39 + (4q - 5) = 90°

<u>Solution:</u>

  • 34 + 4q = 90°
  • => 4q = 90 - 34
  • => 4q = 56
  • => q = 56/4
  • => q = 14

Hence, the value of q is 14.

7 0
2 years ago
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Estimate the percent of the number.<br> ​11% of 504
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55 is the estimated answer
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2 years ago
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the net of the rectangular prism is shown below. use a ruler to measure the dimensions of the net to the nearest half centimeter
Arte-miy333 [17]

Answer:

the answer is D.  40.5 cm

8 0
3 years ago
A small business owner estimates his mean daily profit as $970 with a standard deviation of $129. His shop is open 102 days a ye
Katena32 [7]

Answer:

The probability that the shopkeeper's annual profit will not exceed $100,000 is 0.2090.

Step-by-step explanation:

According to the Central Limit Theorem if we have a population with mean <em>μ</em> and standard deviation <em>σ</em> and we select appropriately huge random samples (<em>n</em> ≥ 30) from the population with replacement, then the distribution of the sum of values of <em>X</em>, i.e ∑<em>X</em>, will be approximately normally distributed.  

Then, the mean of the distribution of the sum of values of X is given by,  

 \mu_{x}=n\mu

And the standard deviation of the distribution of the sum of values of X is given by,  

 \sigma_{x}=\sqrt{n}\sigma

The information provided is:

<em>μ</em> = $970

<em>σ</em> = $129

<em>n</em> = 102

Since the sample size is quite large, i.e. <em>n</em> = 102 > 30, the Central Limit Theorem can be used to approximate the distribution of the shopkeeper's annual profit.

Then,

\sum X\sim N(\mu_{x}=98940,\ \sigma_{x}=1302.84)

Compute the probability that the shopkeeper's annual profit will not exceed $100,000 as follows:

P (\sum X \leq  100,000) =P(\frac{\sum X-\mu_{x}}{\sigma_{x}}

                              =P(Z

*Use a <em>z</em>-table for the probability.

Thus, the probability that the shopkeeper's annual profit will not exceed $100,000 is 0.2090.

6 0
2 years ago
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