Answer:
Step-by-step explanation:
Let call:
x₁ number of units of product 1
x₂ number of units of product 2
We build the next table
metal frame electrical components Profit $/u
Product 1 (x₁) 1 2 13
Product 2 (x₂) 3 2 26(*)
Total supply ( in units) 3000 4500
(*) Up to 900 units . each unit above that number has to be ruled out
From the above table we have:
Objective function z
z = 13*x₁ + 26*x₂ to maximize
1*x₁ + 3*x₂ ≤ 3000
2*x₁ + 2*x₂ ≤ 4500
x₁ ≥ 0 ; 900 ≥ x₂ ≥ 0
Rearranging
z - 13* x₁ - 26*x₂ = 0
0 + x₁ +3*x₂ ≤ 0
0 + 2*x₁ +2*x₂ ≤ 0
x₁ ≥ 0
0 ≤ x₂ ≤ 900
Or
z - 13* x₁ - 26*x₂ = 0
0 + x₁ +3*x₂ + s₁ + 0s₂ = 0
0 + 2*x₁ +2*x₂ + 0s₁ + s₂ = 0
x₂ + 0s₁ + 0s₂ + s₃ = 900
x₁ ≥ 0 x₂ ≥ 0
And the table is ready for use Simplex Method
Let 
and 
be the amounts of available alloy (AA) and pure magic steel that are used, so we also have
DA13 is supposed to contain 7% gold, 3% silver, and 90% steel, so that 2.7 kg of it is made up of
For each kg of the available alloy (AA), there is a contribution of 0.21 kg of gold, 0.09 kg of silver, and therefore 0.70 kg of steel; kg of it will contain 
kg of gold, 
kg of silver, and 
kg of steel. Each kg of magic steel of course contributes 1 kg of steel; kg of it will contribute kg of steel.
Then the dwarves need
• total gold: 
• total silver: 
• total steel: 
Solve for and . The first two equations are consistent and give 
, and substituting this into the third we find 
. So the dwarves must combine 0.90 kg of AA and 1.80 kg of magic steel.
Answer:
i believe its the second one.
Step-by-step explanation:
the second line plot is the one that seems most right to me
X -length
y wide
x=4y
2x+2y=12,5
x=4y
8y+2y=12,5
x=4y
y=1,25
x=5
y=1,25
area
x*y=5*1,25=6,25
