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lutik1710 [3]
3 years ago
10

Maths help please!!!!!!

Mathematics
1 answer:
ddd [48]3 years ago
4 0

Answer:

VW = √2

Step-by-step explanation:

y = x+1

x²+y²+2x+2y+1=0          (x²+2x+1) + (y²+2y+1) = 1

(x+1)² + (y+1)² = 1  : Circle: (x-h)² + (y-k)² = r²     Center (O): (h , k) = (-1 , -1) r = 1

solve for roots: x²+(x+1)²+2x+2(x+1)+1=0

2x² + 6x + 4 = 0          x²+3x+2=0

(x+1)(x+2)=0

x = -1 or x = -2

y = 0 or y = -1

V and W: (-1 , 0) and (-2 , -1)  forms a 90° center angle

√vw = √1²+1² = √2

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(0.13-0.1) - 2.58 \sqrt{\frac{0.13(1-0.13)}{165} +\frac{0.10(1-0.10)}{140}}=-0.0664  

(0.13-0.1) + 2.58 \sqrt{\frac{0.13(1-0.13)}{165} +\frac{0.10(1-0.10)}{140}}=0.124  

We are confident at 99% that the difference between the two proportions is between -0.0664 \leq p_1 -p_2 \leq 0.124 . And since the confidence interval cotains the value 0 we don't have enough evidence to conclude that we have significant differences between the to proportions in these two cities

Step-by-step explanation:

p_1 represent the real population proportion for 1

\hat p_1 =\frac{22}{165}=0.13 represent the estimated proportion for 1

n_1=165 is the sample size required for 1

p_2 represent the real population proportion for 2

\hat p_2 =\frac{14}{140}=0.10 represent the estimated proportion for 2

n_2=140 is the sample size required for 2

z represent the critical value for the margin of error  

The confidence interval for the difference of two proportions would be given by this formula  

(\hat p_1 -\hat p_2) \pm z_{\alpha/2} \sqrt{\frac{\hat p_1(1-\hat p_1)}{n_1} +\frac{\hat p_2 (1-\hat p_2)}{n_2}}  

For the 99% confidence interval the significance is \alpha=1-0.99=0.01 and \alpha/2=0.005, and the critical value using the normal standard distribution.  

z_{\alpha/2}=2.58  

Replacing we got:

(0.13-0.1) - 2.58 \sqrt{\frac{0.13(1-0.13)}{165} +\frac{0.10(1-0.10)}{140}}=-0.0664  

(0.13-0.1) + 2.58 \sqrt{\frac{0.13(1-0.13)}{165} +\frac{0.10(1-0.10)}{140}}=0.124  

We are confident at 99% that the difference between the two proportions is between -0.0664 \leq p_1 -p_2 \leq 0.124 . And since the confidence interval cotains the value 0 we don't have enough evidence to conclude that we have significant differences between the to proportions in these two cities

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Part A) A- 2:2 B- 4:4 C- -4:2

A1- 2:-2 B1- 4:-4 C1- -4:-2
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