Solve this parallelogram angle

Mathematics

2 answers:

Vesnalui [34]2 years ago

7 0

Answer:

103

Step-by-step explanation:

angles formed on the same line of a parallelogram are supplementary angles

( the angle with the measure of 77 degrees and the angle labeled "x" are formed on the same line which means they are supplementary )

supplementary angles add up to equal 180

hence, 77 + x = 180

180 - 77 = 103

Hence, x = 103

notka56 [123]2 years ago

4 0

Answer:

103°

Step-by-step explanation:

sum of angles of quadrilateral = 180°

<h3>Simplify:</h3>

77° + x° = 180°

x° = 180° - 77°

x° = 103

<h3>Hope it is helpful....</h3>

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Answer:

$a + b + c = \pi \\ = > c= \pi - a - b \\ < = > \tan(c) = \tan(\pi - a - b) = -\tan(a + b)$

Step-by-step explanation:

we have:

$\tan(a) + \tan(b) + \tan(c) \\ = \tan(a) + \tan(b) - \tan(a + b) \\ = \tan( a) + \tan(b) - \frac{ \tan(a) + \tan(b) }{1 - \tan(a) \tan(b) } \\ = \frac{ ( \tan(a) + \tan(b) ) \tan(a) \tan(b) }{ \tan(a) \tan(b) - 1 } (1)$

we also have:

$\tan(a) \tan(b) \tan(c) \\ = - \tan(a) \tan(b) \tan(a + b) \\ = \frac{ -(\tan( a ) + \tan(b) ) \tan(a) \tan(b) }{1 - \tan(a) \tan(b) } \\ = \frac{( \tan(a) + \tan(b)) \tan(a) \tan(b) }{ \tan(a) \tan(b) - 1 } (2)$