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marta [7]
3 years ago
14

Please help! Which line would be perpendicular?

Mathematics
1 answer:
givi [52]3 years ago
8 0

Answer:

  • D. -2x + 2y = 1

Step-by-step explanation:

<u>When the line is given in standard form:</u>

  • ax + by = c, it has slope of -a/b

<u>Given line:</u>

  • 4x + 4y = 3

<u>It has a slope:</u>

  • m = -4/4 = -1

A line perpendicular to the given should have a slope m = 1 as negative reciprocal to the given

<u>Let's see which line has the slope of 1:</u>

  • 1. m = -(-1)/6 = 1/6 - NO
  • 2. m = -4/4 = -1 - NO
  • 3. m = -2/4 = -1/2 - NO
  • 4. m = -(-2)/2 = 1 - YES

Correct option is D

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Find the first five terms of the sequence in which a1 = –10 and an = 4an – 1 + 7, if n ≥ 2.
Naddika [18.5K]

Answer:

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Step-by-step explanation:

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4 years ago
How do I solve a given right triangle to find Cos, Sin, and Tan. How do I solve for a missing adjacent side? (For Example: Imagi
Sphinxa [80]

The steps to find cos, sin, and tan and missing adjacent side of a given right angle triangle is explained.

<u>Solution:</u>

Given, a right triangle with A, B, and C.  

Opposite side = 70 inches  

Hypotenuse = 12 feet = 12 \times 12 inches = 144 inches

Adjacent side = "x" inches.  

We are not given angle, so we have to use the hypotenuse theorem

Hypotenuse theorem  means square of the length of the hypotenuse is equal to the sum of squares of the lengths of other two sides of the right-angled triangle.

\text { hypotenuse }^{2}=(\text { opposite side })^{2}+(\text { adjacent side })^{2}

Substituting the values we get,

\begin{array}{l}{\rightarrow 144^{2}=70^{2}+x^{2}} \\\\ {\rightarrow x^{2}=20736-4900} \\\\ {\rightarrow x^{2}=15836} \\\\ {\rightarrow x=\sqrt{15836}} \\\\ {\rightarrow x=125.841}\end{array}

So, the adjacent side value is 125.8 inches approximately.

Hence the steps to find adjacent side is shown above

Now let us find cos, sin and tan

\begin{aligned} \sin \theta &=\frac{\text {opposite side}}{\text {hypotenuse}} \\\\ \cos \theta &=\frac{\text {adjacent side}}{\text {hypotenuse}} \\\\ \tan \theta &=\frac{\text {opposite side}}{\text {adjacent side}} \end{aligned}

By substituting the required values, we can find cos, sin and tan

\begin{array}{l}{\sin \theta=\frac{70}{144}=\frac{35}{122}} \\\\ {\cos \theta=\frac{125.8}{144}=\frac{62.9}{122}} \\\\ {\tan \theta=\frac{70}{125.8}=\frac{35}{62.9}}\end{array}

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Answer:

C)

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