3 years ago

If you know this please help

Mathematics

1 answer:

Anuta_ua [19.1K]3 years ago

4 0

Answer:

its c hope this helps:)

Step-by-step explanation:

You might be interested in

Simplify, don’t solve for x, just simplify, write it with only one x and no parenthesis:

Mamont248 [21]

2(4x-1) + 3x = 8x - 2 + 3x

= 11x - 2

Hope this helps

7 0

3 years ago

Find the Area of each triangle using a^2 +b^2 =c^2 and A=bh/2

ArbitrLikvidat [17]

I rearranged the Pythagorean Theorem so I wouldn’t have to always isolate. Also Q1 couldn’t fit in the picture so I’ll write the solution here.

A = bh/2
= (5.8)(15.2)/2
= 44.08m2

Hope this helps :)

8 0

3 years ago

WHO CAN HELP ME ITS DUE IN 5 minutes!

Flura [38]

We have to find b first: 3 = -3/2(10)+b3 = -15+b18 = bNow right the equation, your slope will be the same one....Y = -3/2x + 18

8 0

3 years ago

Use the table of integrals, or a computer or calculator with symbolic integration capabilities, to find the indefinite integral.

nignag [31]

Answer:

$-\frac{3}{11}\ln(\cot t + \csc t)+C$

Step-by-step explanation:

We are given: $\int \frac{3}{x\sqrt{121-x^2}} dx$

We will use integration by parts.

$x = 11 \sin t\\dx = 11 \cos t \: dt$

$\int \frac{3}{x\sqrt{121-x^2}} dx=\int \frac{3* 11 \cos t \: dt}{11 \sin t\sqrt{121-121\sin^2 t}} =\int \frac{3* 11 \cos t \: dt}{11 \sin t*11\cos t}} =\\\\= \frac{3}{11} \int \csc t = -\frac{3}{11}\ln(\cot t + \csc t)+C$

4 0

4 years ago

A school has 375 boys and 405 girls.What percentage (correct to one decimal place) are boys?

Marysya12 [62]

Total students = 375 + 405 = 780

boys % = (375 / 780) *100%
=48.1 %

6 0

3 years ago