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11Alexandr11 [23.1K]
3 years ago
9

Drag the missing statements and reasons to the correct spot to complete the proof

Mathematics
1 answer:
morpeh [17]3 years ago
7 0

Answer:

See attached

Step-by-step explanation:

Answer is attached

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Use compatible numbers to find two estimates
taurus [48]
Use compatible numbers to find two estimates that the quotient is between. For example: 

1,624 divided by 3
<span> 1500 / 3 = 500 </span>

<span>1800 / 3 = 600</span>
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3 years ago
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The sum of the interior angles of a quadrilateral ___ the sum of its exterior angles. Select one: a. &gt; b. &lt; c. equals
viktelen [127]

Answer:

The sum of the interior angles of a quadrilateral <u>equals</u><u> </u> the sum of its exterior angles.

Step-by-step explanation:

The sum of the exterior angles of a quadrilateral is 360 degrees.

The sum of the interior angles = (n-2)*180

Here n = 4, the number of sides.

Quadrilateral has 4 sides.

The sum of the interior angles = (4 - 2)*180

= 2*180

= 360 degrees.

Therefore, the sum of the interior angles of a quadrilateral <u>equals </u> the sum of its exterior angles.

Hope this will helpful.

Thank you.

6 0
2 years ago
Solve the equation below <br> 9 = x/18 <br> x=<br> What is X?
dedylja [7]
X=162, if you multiply 18*9 which is the way to get the answer you get 162
7 0
2 years ago
Please help please please
Liula [17]

Length of shorter piece is 13 ft

Length of longer piece is 61 - 13 => 48 ft

5 0
3 years ago
Find the solution to the initial value problem
Karo-lina-s [1.5K]

Answer:

y = (11x + 13)e^(-4x-4)

Step-by-step explanation:

Given y'' + 8y' + 16 = 0

The auxiliary equation to the differential equation is:

m² + 8m + 16 = 0

Factorizing this, we have

(m + 4)² = 0

m = -4 twice

The complimentary solution is

y_c = (C1 + C2x)e^(-4x)

Using the initial conditions

y(-1) = 2

2 = (C1 -C2) e^4

C1 - C2 = 2e^(-4).................................(1)

y'(-1) = 3

y'_c = -4(C1 + C2x)e^(-4x) + C2e^(-4x)

3 = -4(C1 - C2)e^4 + C2e^4

-4C1 + 5C2 = 3e^(-4)..............................(2)

Solving (1) and (2) simultaneously, we have

From (1)

C1 = 2e^(-4) + C2

Using this in (2)

-4[2e^(-4) + C2] + 5C2 = 3e^(-4)

C2 = 11e^(-4)

C1 = 2e^(-4) + 11e^(-4)

= 13e^(-4)

The general solution is now

y = [13e^(-4) + 11xe^(-4)]e^(-4x)

= (11x + 13)e^(-4x-4)

3 0
3 years ago
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