3 years ago

12-2/3x=x-18 so how do you answer this question

Mathematics

1 answer:

vitfil [10]3 years ago

3 0

Answer:

Step-by-step explanation:

I think I've already answered this question.

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Please help

ASHA 777 [7]

Answer:

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Step-by-step explanation:

The equations are:

$x^2+4y^2=100\\4y-x^2=-20$

Solving for x^2 of the 2nd equation and putting that in place of x^2 in the 2nd equation we have:

$4y-x^2=-20\\x^2=4y+20\\-------\\x^2+4y^2=100\\4y+20+4y^2=100$

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$4y+20+4y^2=100\\4y^2+4y-80=0\\y^2+y-20=0\\(y+5)(y-4)=0\\y=4,-5$

So plugging in y = 4 into an equation and solving for x, we have:

$x^2=4y+20\\x=+-\sqrt{4y+20} \\x=+-\sqrt{4(4)+20} \\x=+-\sqrt{36} \\x=6,-6$

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The pairs would be

(6,4) & (-6,4)

we see that (-6,4) falls in the 2nd quadrant, thus this is the solution we are looking for.

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