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Shtirlitz [24]
3 years ago
5

Write a function longer_string() with two string input parameters that returns the string that has more characters in it. If the

strings are the same size, return the string that occurs later according to the dictionary order. Use the function in a program that takes two string inputs, and outputs the string that is longer.
Computers and Technology
1 answer:
BartSMP [9]3 years ago
4 0

Answer:

Here you go :)

Explanation:

Change this to your liking:

def longer_string(s1, s2):

   if len(s1) > len(s2):

       return s1

   elif len(s1) < len(s2):

       return s2

   else:

       return s2

x = input("Enter string 1: ")

y = input("Enter string 2: ")

print(longer_string(x, y))

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Which of the following Access objects provides a user-friendly data entry method?
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Answer:

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Microsoft Access uses an object called a _____ to enter and organize data.

The answer is table.

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Explanation:

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Write code for a function with the following prototype: /* Addition that saturates to TMin or TMax */ int saturating_add(int x,
Kazeer [188]

Answer:

See explaination

Explanation:

program code.

/* PRE PROCESSOR DIRECTIVES */

#include<stdio.h>

/* PRE-DEFINED VALUES FOR TMAX AND TMIN */

#define TMax 2147483647

#define TMin (-TMax -1)

/* saturating_add(int,int) METHOD IS CALLED HERE */

int saturating_add(int firstNumber, int secondNumber)

{

/*

FOR BETTER UNDERSTANDING, LETS TAKE TEST CASE,

WHERE firstNumber = 5 AND secondNumber = 10

*/

int w = sizeof(firstNumber) << 3;

/*

sizeof(firstNumber) VALUE IS 4, SO USING BINARY LEFT SHIFT OPERATOR TO THREE PLACES,

WE HAVE NOW VALUE 32, ASSIGNED TO w

*/

/* ADDITION IS CALCULATED => 15 */

int addition = firstNumber + secondNumber;

/*

MASK INTEGER VARIABLE IS TAKEN

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*/

int mask = 1 << (w - 1);

/* FIRST NUMBER MOST SIGNIFICANT BIT IS CALCULATED BY USING AND OPERATOR */

int msbFirstNumber = firstNumber & mask;

/* SECOND NUMBER MOST SIGNIFICANT BIT IS CALCULATED BY USING AND OPERATOR */

int msbSecondNumber = secondNumber & mask;

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int msbAddition = addition & mask;

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int positiveOverflow = ~msbFirstNumber & ~msbSecondNumber & msbAddition;

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int negativeOverflow = msbFirstNumber & msbSecondNumber & !msbAddition;

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(positiveOverflow) && (addition = TMax);

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}

/* MAIN FUNCTION STARTS HERE */

int main(){

/* TEST CASE */

int sum = saturating_add(5, 10);

/* DISPLAY THE RESULT OF TEST CASE */

printf("The Sum Is : %d\n\n",sum);

}

7 0
4 years ago
This is the formula for the future worth of an investment over time with consistent additional monthly payments and a steady rat
stepladder [879]

Answer:

The code is given in C++ below

Explanation:

#include <iostream>

using namespace std;

int main()

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float fv,pv,r,k,n,pmt,totalmoneyinvested;

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cout<<"\nFinal Amount:"<<" $"<<fv;

cout<<"\nThe Money You Invested Is $"<<totalmoneyinvested<<" And The Final Amount Is $"<<fv;

return 0;

}

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7 0
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