Answer:
The correct answer is-
F1 - AaBb (lacerate)
F2 - A_B_; A_bb; and aaB_ (lacerate)
- aabb (normal)
2. Two genes, with a dominant allele at either or both loci.
Explanation:
The given information gives THE following data:
Dominant: Lancerate leaves - AABB
Recessive: normal leaves - aabb
F1 has - all Lacerated leaves - AaBb
F2 by selfing F1:
AB Ab aB ab
AB AABB AABb AaBB AaBb
Ab AABb AAbb AaBb Aabb
aB AaBB AaBb aaBB aaBb
ab AaBb Aabb aaBb aabb
Here, 15/16 = lacerate which is 0.94 which is equal to the value of lacerate given in the question - 249/265 = 0.94
And normal 1/16 = 0.062 is almost same as 16/265 = 0.060
Thus, the genotypes of -
F1 - AaBb (lacerate)
F2 - A_B_; A_bb; and aaB_ (lacerate)
- aabb (normal)
Answer: Comparing the rates of predation on whitefly nymphs coated with a nontoxic dye versus the undyed whitefly nymphs.
Explanation:
A hypothesis refers to an assumption, which is proposed for the sake of an argument which is tested to ascertain if it's true.
The hypothesis can be tested by comparing the rates of predation on whitefly nymphs coated with a nontoxic dye versus the undyed whitefly nymphs.
The major cells of the ground tissue are parenchyma cells, which function in photosynthesis and nutrient storage. They have thin walls, many chloroplasts, and large central vacuoles, and they form the mass of most leaves, stems, and roots. Another cell of the ground substance is the sclerenchyma cell.
Hope that helped! sorry if its wrong
To all parts but particularly u can say phloem sap
