Answer:
The solution of a system of linear equations is:
D. The values of the variables that satisfy both equations.
Answer:

Step-by-step explanation:
We see that the two terms share an x, so we can pull that out:

Now notice that we have a difference of squares (
). Given a difference of squares,
, this can always be factored into
. We can use this in this case:
.
So, our final factorized form is:
.
Hope this helps!
Answer: 0.9730
Step-by-step explanation:
Let A be the event of the answer being correct and B be the event of the knew the answer.
Given: 


If it is given that the answer is correct , then the probability that he guess the answer 
By Bayes theorem , we have


Hence, the student correctly answers a question, the probability that the student really knew the correct answer is 0.9730.
Make 2 graphs and with the second graph graph the cell fee and with the first Do the minutes