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3 years ago

The nth term formula of a sequence is given as Tn = 5n+1. Use it to find the first 5 terms of squence

Mathematics

1 answer:

Sergeeva-Olga [200]3 years ago

8 0

Answer:

The first 5 terms are $6,11,16,21,26$

Step-by-step explanation:

Given: $T_n=5n+1$

To find: the first 5 terms of sequence

Solution:

To find the first 5 terms of sequence, put $n=1,2,3,4,5$ in $T_n=5n+1$

$T_1=5(1)+1=5+1=6\\T_2=5(2)+1=10+1=11\\T_3=5(3)+1=15+1=16\\T_4=5(4)+1=20+1=21\\T_5=5(5)+1=25+1=26$

So, the first 5 terms are $6,11,16,21,26$

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Write 2x3 − 3x2 + x5 in standard form. What is the classification of this polynomial by its degree? by its number of terms?

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Answer:

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Aleksandr [31]

Answer:

About 527.79

Step-by-step explanation:

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Read 2 more answers

A. Complete the table if y varies

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Direct variation is represented by the equation y = k × x and inverse variation is represented by y = k/x

Table 1:

y = k × x

30 = k × 5

30 = 5k

k = 30/5

k = 6

So,

y = 30

y = 30 k = 6

y = 30 k = 6x = 5

y = 30 k = 6x = 5Equation: y = 6x

y = k × x

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y = 80

So,

y = 80

y = 80 k = 10

y = 80 k = 10x = 8

y = 80 k = 10x = 8Equation: y = 10x

y = 3x

18 = 3x

x = 18/3

x = 6

So,

y = 18

y = 18k = 3

y = 18k = 3x = 6

y = 18k = 3x = 6Equation: y = 3x

y = 2x²

72 = 2x²

x² = 72/2

x² = 36

x = √36

x = 6

So,

y = 72

y = 72k = 2

y = 72k = 2x = 6

y = 72k = 2x = 6Equation: y = 2x²

Table 2:

y = k/x

5 = k/6

5 × 6 = k

30 = k

So,

y = 5

y = 5k = 30

y = 5k = 30x = 6

y = 5k = 30x = 6Equation: y = 30/x

y = k/x

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y = 9

So,

y = 9

y = 9k = 36

y = 9k = 36x = 4

y = 9k = 36x = 4Equation: y = 36/x

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20 = 60/x

20x = 60

x = 60/20

x = 3

So,

y = 20

y = 20k = 60

y = 20k = 60x = 3

y = 20k = 60x = 3Equation: y = 60/x

y = 24/x

y = 24/12

y = 2

So,

y = 2

y = 2k = 24

y = 2k = 24x = 12

y = 2k = 24x = 12Equation: y = 24/x

brainly.com/question/472621

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