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Dmitry [639]
3 years ago
11

The top one is the last one I need help plz

Mathematics
1 answer:
lisov135 [29]3 years ago
3 0

Answer:

hh

Step-by-step explanation:

hh

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Tom fed his chickens with grains on Sun. The chickens ate a 1/4 of what was given to them that day. On Mon, the chickens ate a 1
SVETLANKA909090 [29]

Answer:

1/2

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
Kimmy has 47 ft.² of cement blocks each square block has size 1 foot long what is the greatest perimeter of a rectangle that she
blagie [28]

Answer:

The larges perimeter she can make becomes is 96 ft

Step-by-step explanation:

Here we note that the available brick is 47 ft²

Therefore, she has 47 square cement blocks

Let the length of the sides of the rectangle with the most perimeter be x and y

Then 2·x + 2·y = 47 which is not possible because 47 is a prime number

Hence we have the possible sides of the rectangle is a single line of square blocks such that

x × y  = 47 ft² where y = 1 hence x = 47

The larges perimeter she can make becomes, 2 × (1 + 47) = 96 ft.

3 0
4 years ago
The number of coffee shops in a certain country can be modeled by the quadratic function ​f(x)105x²+680x+4296, where​ f(x) is th
grigory [225]

A. X is the number of years after 2000

2006-200 = 6 years.

Replace x with 6 and solve:

105(6)^2 + 680(6) + 4296 = 12,156


Answer for part a: 12,156


Answer for part B.
There was just over 12,000 in 6 years , to get to 21,500 would be a little over 9,000 more 9/12 = 0.75

6 years x .75 = 4.5 years


6 + 4.5 = 10.5 years round to 10 years for estimating purposes


Answer for part b: about 10 years

7 0
2 years ago
Estimate the following difference using front-end estimation. 788.44 - 225.6
Liula [17]

Answer:

562.84

Step-by-step explanation:

5 0
4 years ago
1. A coal train in Montana starts from rest and accelerates at 2.5 m/s2 for 15s.
liq [111]

Answer:

<h3>37.5m/s</h3>

Step-by-step explanation:

If a coal train in Montana starts from rest and accelerates at 2.5 m/s2 for 15s,let us calculate the final velocity of the train.

Use the equation of motion v = u + at where;

v is the final velocity

u is the initial velocity = 0m/s (starts from rest)

a is the acceleration = 2.5m/s²

t is the time = 15secs

Substituting the given parameters into the formula;

v = 0+(2.5)(15)

v = 0+37.5

v = 37.5m/s

Hence the final velocity of the train is 37.5m/s

8 0
3 years ago
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