Answer:
A circle is centered at the point (-3,2) and passes through the point (1,5). The radius of the circle is (5 ) units. the point (-7, -1) and point (-7, 5) lies in this circle.
Step-by-step explanation:
equation of circle is
(X-center_X)^2 + (y-center_Y)^2 = r^2
==> (x+3)^2 + (y-2)^2 = r^2
Now it passes 1,5 so
4^2+3^2 = 5^2
==> r = 5
when x = -7
y = -1 or 5
Step-by-step explanation:
[ Refer to the attachment ]
F(x)=x^2+2x+1 & g(x)=3(x+1)^2
now, f(x)+g(x)
=x^2+2x+1+3(x+1)^2
=x^2+2x+1+3(x^2+2x+1)
=x^2+2x+1+3x^2+6x+3
=4x^2+8x+4<===answer(c)
next:
f(x)=x^2-1 & g(x)=x+3
now, f(g(x))=(x+3)^ -1
=x^2+6x+9-1
=x^2+6x+8<====answer(b)
i solve two of ur problems.
now try the 3rd one that is similar to no. 1
and try the last two urself.
Answer:
Component form : (-7 , 2)
Step-by-step explanation:
P(4 , 5) = P'(4 +x , 5+y) = P'(-3 , 7)
4 + x = -3
x = -3 - 4
x = -7
5 + y = 7
y = 7 - 5
y = 2
Vector form : -7i + 2j
Component form : (-7 , 2)
Answer:
Step-by-step explanation:
