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Solnce55 [7]
3 years ago
7

In the service department of the Glenn-Mark Auto Agency, mechanics requiring parts for auto repair or service present their requ

est forms at the parts department counter. The parts clerk fills a request while the mechanic waits. On average everyday around 210 mechanics arrive in a random fashion over 10-hour working period. It takes the clerk average 2 minutes to fill a request. Assuming the service time and inter-arrival time is random and exponentially distributed. a) What is the average time mechanics spend waiting and having requests filled under the current system
Mathematics
1 answer:
Anton [14]3 years ago
6 0

Answer:

the average time spend is 0.111

Step-by-step explanation:

The computation of the average time spend is as follows;

Arrival rate is

= 210 ÷ 10

= 21 per hour

Now the service rate is

= 60 ÷ service time

= 60 ÷ 2 minutes

= 30 per minute

And, finally the average time spend is

= 1 ÷ (service rate - arrival rate)

= 1 ÷ (30 - 21)

= 0.111

Hence, the average time spend is 0.111

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149.99 x 7/100 = $10.50 which is the TAX

and then add that to the original price 

10.50 + 149.99 = 160.49
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Find the value of the expression when x=1 and y=4. 7x+4+5=
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Step-by-step explanation:

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Read 2 more answers
Please show full solutions! WIll Mark Brainliest for the best answer. <br><br> SERIOUS ANSWERS ONLY
Ierofanga [76]

Answer:

  • vertical scaling by a factor of 1/3 (compression)
  • reflection over the y-axis
  • horizontal scaling by a factor of 3 (expansion)
  • translation left 1 unit
  • translation up 3 units

Step-by-step explanation:

These are the transformations of interest:

  g(x) = k·f(x) . . . . . vertical scaling (expansion) by a factor of k

  g(x) = f(x) +k . . . . vertical translation by k units (upward)

  g(x) = f(x/k) . . . . . horizontal expansion by a factor of k. When k < 0, the function is also reflected over the y-axis

  g(x) = f(x-k) . . . . . horizontal translation to the right by k units

__

Here, we have ...

  g(x) = 1/3f(-1/3(x+1)) +3

The vertical and horizontal transformations can be applied in either order, since neither affects the other. If we work left-to-right through the expression for g(x), we can see these transformations have been applied:

  • vertical scaling by a factor of 1/3 (compression) . . . 1/3f(x)
  • reflection over the y-axis . . . 1/3f(-x)
  • horizontal scaling by a factor of 3 (expansion) . . . 1/3f(-1/3x)
  • translation left 1 unit . . . 1/3f(-1/3(x+1))
  • translation up 3 units . . . 1/3f(-1/3(x+1)) +3

_____

<em>Additional comment</em>

The "working" is a matter of matching the form of g(x) to the forms of the different transformations. It is a pattern-matching problem.

The horizontal transformations could also be described as ...

  • translation right 1/3 unit . . . f(x -1/3)
  • reflection over y and expansion by a factor of 3 . . . f(-1/3x -1/3)

The initial translation in this scenario would be reflected to a translation left 1/3 unit, then the horizontal expansion would turn that into a translation left 1 unit, as described above. Order matters.

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2 years ago
How to graph the slope for<br> y=5x +2
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Answer:

see attatched image

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