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White raven [17]
3 years ago
14

What is the transformations in the following quadratic function y=5(x + 3)3 – 5

Mathematics
1 answer:
Mariulka [41]3 years ago
6 0
You should have you answer as

X = -8/3

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The graph of a proportional relationship passes through (12,16) and (1,y). find y​
anastassius [24]

Answer:

4/3

Step-by-step explanation:

A proportional relationship is a relationship that crosses through the origin or (0,0). This means the slope of the line can be found by subtracting the points (12,16) and (0,0) in the slope formula.

m = \frac{y_2-y_1}{x_2-x_1} =\frac{16-0}{12-0}= \frac{16}{12}=\frac{4}{3}

So the slope is 4/3 and must be the value between any two points on the line.

This means the function moves from (0,0) to (1, 4/3).

4 0
4 years ago
A scale drawing of Juanita‘s back porch is shown.
Zepler [3.9K]

Answer:

1 inch

Step-by-step explanation:

IT ONE INCH NOW HURRY!!!

6 0
3 years ago
Use the given figure to find the length of FG
ra1l [238]
ANSWER

|FG| = 19 \: units




EXPLANATION


Since the altitude, |GJ| bisects the base of the triangle, it follows that, the triangle is an isosceles triangle.



This implies that,.

|FG|=|GH|

In terms of x, we have the equation.


5x - 6 = 3x + 4


We now group like terms to obtain,



5x - 3x = 4 + 6


This implies that,


2x = 10

Let us divide through by 2 to get,



x = 5

We can see from the diagram that,


|FG|=5x-6

We substitute x=5 to get,


|FG|=5(5)-6


This simplifies to,


|FG|=25-6


|FG|=19 \: units
3 0
3 years ago
Find the fourth point of a parallelogram given the first three (more than one correct answer is possible): (0,6), (5, -1) and (3
inysia [295]

Answer:

The fourth point of the parallelogram is one point among (-2,2), (2,10) and (8,-12).

Step-by-step explanation:

Given information: The first three vertices of parallelogram are (0,6), (5, -1) and (3,-5).

Let fourth point of the parallelogram is (a,b).

Diagonals of a parallelogram bisect each other. It means midpoint of both diagonals are same.

Midpoint formula:

Midpoint=(\frac{x_1+x_2}{2},\frac{y_1+y_2}{2})

Case 1: If the point (0,6), (5, -1) and (3,-5) are consecutive, then pairs of opposite vertices are (0,6) and (3,-5), (5,-1) and (a,b).

(\frac{0+3}{2},\frac{6-5}{2})=(\frac{5+a}{2},\frac{-1+b}{2})

(\frac{3}{2},\frac{1}{2})=(\frac{5+a}{2},\frac{-1+b}{2})

On comparing both sides, we get

\frac{3}{2}=\frac{5+a}{2}

3=5+a

a=-2

\frac{1}{2}=\frac{-1+b}{2}

1=-1+b

b=2

It means the fourth point of the parallelogram is (-2,2).

Case 2: If the point (0,6), (5, -1) and (3,-5) are not consecutive, then pairs of opposite vertices are (0,6) and (5,-1), (3,-5) and (a,b).

(\frac{0+5}{2},\frac{6-1}{2})=(\frac{3+a}{2},\frac{-5+b}{2})

(\frac{5}{2},\frac{5}{2})=(\frac{3+a}{2},\frac{-5+b}{2})

On comparing both sides, we get

\frac{5}{2}=\frac{3+a}{2}

5=3+a

a=2

\frac{5}{2}=\frac{-5+b}{2}

5=-5+b

b=10

It means the fourth point of the parallelogram is (2,10).

Case 3: If the point (0,6), (5, -1) and (3,-5) are not consecutive, then pairs of opposite vertices are (5,-1) and (3,-5), (0,6) and (a,b).

(\frac{5+3}{2},\frac{-1-5}{2})=(\frac{0+a}{2},\frac{6+b}{2})

(\frac{8}{2},\frac{-6}{2})=(\frac{a}{2},\frac{6+b}{2})

On comparing both sides, we get

\frac{8}{2}=\frac{a}{2}

8=a

\frac{-6}{2}=\frac{6+b}{2}

-6=6+b

b=-12

It means the fourth point of the parallelogram is (8,-12).

5 0
4 years ago
Help please much appreciated
larisa [96]
The answer is a.........
6 0
3 years ago
Read 2 more answers
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