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Nina [5.8K]
2 years ago
6

What is the next term of the arithmetic sequence? -2, 3, 8, 13, 18,

Mathematics
2 answers:
Aneli [31]2 years ago
7 0

Answer:

\boxed{\boxed{\sf~a_6=23}}

Solution Steps:

This is an arithmetic sequence since there is a common difference between each term. In this case, adding 5 to the previous term in the sequence gives the next term. In other words, a_n=a_1+d(n-1).

Arithmetic Sequence: d=5

Find the next term using the Arithmetic Sequence.

Arithmetic Sequence: a_6=a_5+5

a_6=18+5=23

Alenkinab [10]2 years ago
4 0
The answer is 23 u add 5 each time
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Can someone plz help me solved this problem I need help ASAP plz help me! Will mark you as brainiest!
lubasha [3.4K]

Answer:

Factored Equation:

A = 4,000,000(1 + r)

If r = 0.14%, the number of bacteria after one hour is calculated by:

4,000,000(1 + 0.14/60)

= 4,000,000(1.002333)

= 4,009,332

After one hour, the petri dish will have produced 4,009,332 bacteria at a growth rate of 0.14%.

Side note: I don't even know if this is right. I just went with what I have.

4 0
3 years ago
Read 2 more answers
Represent fractional percents greater than 100%
Paladinen [302]

Answer:

4/3 6/4 7/2

Step-by-step explanation:

these are all more than 100%

7 0
3 years ago
Read 2 more answers
HELP ME ASAP.. MY TEACHER IS ASKING FOR THE ANSWER ​
Solnce55 [7]

Answer:

a) 10.7 cm

b) 11.6 cm

c) 29.9 cm²

Step-by-step explanation:

a) sin(α)/a = sin(β)/b

sin(∠BCD)/BD = sin(DBC)/DC

sin(41°)/BD = sin(55°)/13.4

BD = 13.4*sin(41°)/sin(55°) = 10.73 cm ≈ 10.7 cm

b) From ΔBCD , ∠BDC = 180-(41+55) = 84°

∠ABD and ∠BDC are alternate interior angles, so they are congruent, and

∠ABD = ∠BDC  = 84°

AD²= AB² + BD² - 2*AB*BD*cos (∠ABD) =

= 5.6² + 10.73² - 2*5.6*10.73*cos(84°) = 133.93 cm²

AD =√(133.93) ≈11.6 cm

c) Area(ADB) = (1/2)*AB*BD*sin(∠ABD)=(1/2)*5.6*10.73*sin(84°) ≈ 29.9 cm²

5 0
3 years ago
A pool measuring 8 meters by 26 meters is surrounded by a path of uniform​ width, as shown in the figure. If the area of the poo
Ainat [17]
Let the width path be x.
Length of the outer rectangle = 26 + 2x.
Width of the outer rectangle = 8 +2x.

Combined Area = (2x + 26)*(2x + 8) = 1008

2x*(2x + 8) + 26*(2x + 8 ) = 1008

4x² + 16x + 52x + 208 = 1008

4x² + 68x + 208 - 1008 = 0
4x² + 68x - 800 = 0.          Divide through by 4.
x²  + 17x - 200 = 0 . This is a quadratic equation.

Multiply first and last coefficients:  1*-200 = -200

We look for two numbers that multiply to give -200, and add to give +17

Those two numbers are 25 and -8.

Check:   25*-8 = -200         25 + -8 = 17

We replace the middle term of +17x in the quadratic expression with 25x -8x


 x² +17x - 200 = 0     

x² + 25x - 8x - 200 = 0     

x(x + 25) - 8(x + 25) = 0

(x+25)(x -8) = 0

x + 25 = 0    or   x - 8 = 0

x = 0 -25              x = 0 + 8

x = -25                    x = 8

The width of the path can not be negative.

The only valid solution is x = 8.

The width of the path is 8 meters.
8 0
3 years ago
Find the midpoint between -7+4i and 3-2i
lana [24]
(-2,3) i believe this is correct
6 0
3 years ago
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