HELP PLEASE

1 answer:

Ber [7]3 years ago

3 0

Ok so 2x4=8 and 8x2=16 so a gallon has 16 cups right and if it takes about 2 cups each servings so u can make like 7 servings with one gallon

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You have two biased coins. Coin A comes up heads with probability 1/4. Coin B comes up heads with probability 3/4. However, you

slega [8]

Answer:

3/4

Step-by-step explanation:

Probability is the likelihood of an event.

No.of favourable outcomes/ Total no. of outcomes

Probability of coin selection : [Both coins have equal likelihood of being chosen]

Prob( Coin A Selection) = 1/2
Prob (Coin B selection) = 1/2

Probability of head & tail by both coins :

Prob (Head / Coin A) = 1/4
Prob (Tail / Coin A) = 1 - [ P (Head/Coin A) ] = 1 - 1/4 = 3/4
Prob (Head / Coin B) = 3/4
Prob (Tail / Coin B) = 1 - [ P (Head/Coin B) ] = 1 - 3/4 = 1/4

Probability of getting head by Coin A : Prob (Coin A) & Prob (Head/CoinA) = 1/2 x 1/4 = 1/8

Probability of getting tail by Coin A : Prob (Coin A) & Prob (Tail/CoinA) = 1/2 x 3/4 = 3/8

Probability of getting head by Coin B : Prob (Coin B) & Prob (Head/CoinB) = 1/2 x 3/4 = 3/8

Probability of getting tail by Coin B : Prob (Coin B) & Prob (Head/CoinB) = 1/2 x 1/4 = 1/8

Probability 'The guess [head from coin B, tail from coin A] :

Prob (Coin A) & Prob (Tail/CoinA) or Prob (Coin B) & Prob (Head/CoinB)

= 3/8 + 3/8 = 3/4

3 0

3 years ago

I forgot how to do this.... can somebody help?

slamgirl [31]

$\bf \qquad \qquad \qquad \qquad \textit{function transformations}
\\ \quad \\\\

\begin{array}{rllll} 
% left side templates
f(x)=&{{ A}}({{ B}}x+{{ C}})+{{ D}}
\\ \quad \\
y=&{{ A}}({{ B}}x+{{ C}})+{{ D}}
\\ \quad \\
f(x)=&{{ A}}\sqrt{{{ B}}x+{{ C}}}+{{ D}}
\\ \quad \\
f(x)=&{{ A}}(\mathbb{R})^{{{ B}}x+{{ C}}}+{{ D}}
\\ \quad \\
f(x)=&{{ A}} sin\left({{ B }}x+{{ C}} \right)+{{ D}}
\end{array}

$

$\bf \begin{array}{llll}
% right side info
\bullet \textit{ stretches or shrinks horizontally by } {{ A}}\cdot {{ B}}\\\\
\bullet \textit{ flips it upside-down if }{{ A}}\textit{ is negative}
\\\\
\bullet \textit{ horizontal shift by }\frac{{{ C}}}{{{ B}}}\\
\qquad if\ \frac{{{ C}}}{{{ B}}}\textit{ is negative, to the right}\\\\
\qquad if\ \frac{{{ C}}}{{{ B}}}\textit{ is positive, to the left}\\\\
\end{array}$

$\bf \begin{array}{llll}


\bullet \textit{ vertical shift by }{{ D}}\\
\qquad if\ {{ D}}\textit{ is negative, downwards}\\\\
\qquad if\ {{ D}}\textit{ is positive, upwards}\\\\
\bullet \textit{ period of }\frac{2\pi }{{{ B}}}
\end{array}$

now, with that template in mind, let's see

3 units to the right, that means C/B = -3 so hmm C = -3 and B = 1 will do, -3/1 = -3

vertical stretch by 2, so A = 2
reflected over the x-axis, so that means is flipped upside-down, so A = -2 then

and shifted down by 3, do D = -3

$\bf f(x)={{ A}}(\mathbb{R})^{{{ B}}x+{{ C}}}+{{ D}}\implies f(x)={{ -2}}(\mathbb{R})^{{{ 1}}x-{{ 3}}}-{{3}}\\\\\\ f(x)={{ -2}}(3)^{{{ }}x-{{ 3}}}-{{3}}$

3 0

4 years ago

-2+{-3}=<br> Helpppp meeee

kondor19780726 [428]

Answer:

-5 should be the answer

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

Re write percentage as a decimal 7.7%

Hitman42 [59]