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Vladimir79 [104]
3 years ago
8

-2+{-3}= Helpppp meeee

Mathematics
2 answers:
Marat540 [252]3 years ago
6 0

Answer:

it should be -5

Step-by-step explanation:

because a negative + a negative = a negative

kondor19780726 [428]3 years ago
3 0

Answer:

-5 should be the answer

Step-by-step explanation:

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Answer:


Step-by-step explanation:

Let's draw the given information first for better understanding . Check the image attached.

We can use cosine rule to find the angles .

for angle A ,

Cos A =\frac{b^2+c^2-a^2}{2bc}

Cos A =\frac{20^2+12^2-15^2}{2*20*12}

Cos A =\frac{319}{480}

m∠A = 48.35 degrees

Similarly for angle B

Cos B =\frac{a^2+c^2-b^2}{2bc}

Cos B =\frac{15^2+12^2-20^2}{2*15*12}

Cos B =\frac{-31}{360}

m∠B = 94.94 degrees

Now use A+B+C=180 degrees

48.35+94.94+C=180

C=180-48.35-94.94

m∠C = 36.71 degrees

3 0
3 years ago
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Set up a proportion.
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3 years ago
Pyramid A has a triangular base where each side measures 4 units and a volume of 36 cubic units. Pyramid B has the same height,
omeli [17]

Answer:

The volume of pyramid B is 81 cubic units

Step-by-step explanation:

Given

<u>Pyramid A</u>

s = 4 -- base sides

V = 36 -- Volume

<u>Pyramid B</u>

s = 6 --- base sides

Required

Determine the volume of pyramid B <em>[Missing from the question]</em>

From the question, we understand that both pyramids are equilateral triangular pyramids.

The volume is calculated as:

V = \frac{1}{3} * B * h

Where B represents the area of the base equilateral triangle, and it is calculated as:

B = \frac{1}{2} * s^2 * sin(60)

Where s represents the side lengths

First, we calculate the height of pyramid A

For Pyramid A, the base area is:

B = \frac{1}{2} * s^2 * sin(60)

B = \frac{1}{2} * 4^2 * \frac{\sqrt 3}{2}

B = \frac{1}{2} * 16 * \frac{\sqrt 3}{2}

B = 4\sqrt 3

The height is calculated from:

V = \frac{1}{3} * B * h

This gives:

36 = \frac{1}{3} * 4\sqrt 3 * h

Make h the subject

h = \frac{3 * 36}{4\sqrt 3}

h = \frac{3 * 9}{\sqrt 3}

h = \frac{27}{\sqrt 3}

To calculate the volume of pyramid B, we make use of:

V = \frac{1}{3} * B * h

Since the heights of both pyramids are the same, we can make use of:

h = \frac{27}{\sqrt 3}

The base area B, is then calculated as:

B = \frac{1}{2} * s^2 * sin(60)

Where

s = 6

So:

B = \frac{1}{2} * 6^2 * sin(60)

B = \frac{1}{2} * 36 * \frac{\sqrt 3}{2}

B = 9\sqrt 3

So:

V = \frac{1}{3} * B * h

Where

B = 9\sqrt 3 and h = \frac{27}{\sqrt 3}

V = \frac{1}{3} * 9\sqrt 3 * \frac{27}{\sqrt 3}

V = \frac{1}{3} * 9 * 27

V = 81

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3 years ago
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C ) sum 

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Answer: 31

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